Answer:
Time needed to empty the pool is 401.35 seconds.
Explanation:
The exit velocity of the water from the orifice is obtained from the Torricelli's law as

where
'h' is the head under which the flow of water occurs
Thus the theoretical discharge through the orifice equals

Now we know that

Thus using this relation we obtain

Now we know by definition of discharge

Using the above relations we obtain

The limits are put that at time t = 0 height in pool = 1.5 m and at time 't' the height in pool = 0
Solving for 't' we get

Answer:
The two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12
Explanation:
The given equation is
Sin x +√3 Cosx= √2
Upon dividing the equation by 2 we get

Sin(
)*Sinx + Cos(
)*Cosx = 
This makes the formula of
CosACosB + SinASinB = Cos(A-B)
Cos(x-
) = 
cos(x- pi/6) = cos(pi/4)
upon writing the general equation we get
x-pi/6 = 2n*pi ± pi/4
x = 2n*pi ± pi/4 -pi/6
so we will have two solutions
x = 2n*pi + pi/4 -pi/6
= 2n*pi + pi/12
and
x = 2n*pi - pi/4 -pi/6
= 2n*pi -5pi/12
Therefore the two values of x are 2n*pi + pi/12 and 2n*pi -5pi/12.
Answer:
<em>The Diameter of an atom that fits into the FCC is 2r,</em>
<em>Which leads to the final steps of 0414R</em>
Explanation:
<em>The diameter of an atom that will fit into the FCC site is (2r) which differentiates length edge unit cell for the radii of two atoms that are seen on both side of the site (R); which is 2r = a – 2R</em>
<em>The FCC is also a part of R, therefore a=2R √2 </em>
<em> Solving for R, the equation is, r =a-2R/2 =2R√2-2R/2 =0414R</em>
Answer:
Clouds
Explanation:
It is created by trapped dust and water.