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natka813 [3]
2 years ago
11

1. Band saw lower wheel does not require a guard * true or false 2. Band saw upper guide should be adjusted to within 1/8" of th

e work piece * true or false 3. Find board & linear ft for 10 pieces of 4" x 4" x 8' *​
Engineering
1 answer:
Blizzard [7]2 years ago
4 0

Answer:

1. Band saw lower wheel does not require a guard * true or false 2. Band saw upper guide should be adjusted to within 1/8" of the work piece * true or false 3. Find board & linear ft for 10 pieces of 4" x 4" x 8' *

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You are given the following information about a drybatch paving operation. You are going to use one mixer that has a service rat
umka21 [38]

Answer:

Answer for the question:

You are given the following information about a drybatch paving operation. You are going to use one mixer that has a service rate of 30 services per hour. The dry-batch trucks you use for bringing concrete to the paver have an arrival rate of 7.5 arrivals per hour. Each truck carries 6 cubic yard of concrete. You have a total amount of 13,500 cubic yard of concrete to pour. You rent a truck at $15 per hour and the paver at $60 per hour. If the job takes more than 80 hours, you pay a penalty of $140 perhour owing todelays injob completion. Onthe basis of least cost, determine the number of trucks you should use. Plot the cost versus the number of trucks used.

is given in the attachment.

Explanation:

5 0
3 years ago
Convert
Helen [10]

Answer:

(a)1.308\times 10^{-4}m/sec

(b)57.33831 pound/cubic feet

(c)120.1095 hp

Explanation:

We have

(a) 760 miles / hour

We know that 1\ mile\ =0.00062m

And 1 hour = 60×60=3600 sec

So 760miles/hour=\frac{760\times 0.00062meter}{3600sec}=1.308\times 10^{-4}m/sec

(b) 927 kg/cubic meter to mass/cubic foot

We know that 1 kg = 2.20 pound

So 921 kg = 921×2.20=2026.2 pound

We know that 1 cubic meter = 35.31 cubic feet

So 57.33831 pound / cubic feet

(c) We have to convert to hp

5.37\times 10^3kj/min=\frac{5.37\times 1000kj}{60sec}=89.5kj/sec

We know that 1 kj /sec = 1.341 hp

So 89.5 kj/sec = 89.5××1.341=120.1095 hp

7 0
4 years ago
A fluid flows through a 10-mm diameter tube at a Reynolds number of 1800. If the flow rate is 6.0 liters/min, what is the head l
Eddi Din [679]

Answer:

29.31 m

Explanation:

It is given that flow rate Q =6.0 ltrs/minute =\frac{6}{1000\times 60} m^3/sec

Diameter =10 mm

So radius =  \frac{10}{2}=5 mm=5\times 10^{-3}m

Area of duct A=\pi r^2=3.14\times(5\times 10^{-3})^2=7.854 \times 10^{-5}m^2

Average velocity v=\frac{Q}{A}=\frac{10^{-4}}{7.854\times 10^{-5}}=1.372 m/sec

The given Reynolds number is 1800 which is less than 2000 so it will be a laminar flow

So Reynolds number friction factor f=\frac{64}{1800}=0.0356

So head loss ifs given by \frac{fLv_{avg}^2}{d\times 2\times g}=\frac{0.0356\times 100\times 1.732^2}{10\times 10^{-3}\times 2\times 9.81}=29.39\ m

5 0
3 years ago
The condition of irrotationality for a two-dimensional flow is satisfied when rotation w everywhere is (less than — equal to — m
Deffense [45]

Answer:

Zero.

Explanation:

Lets take velocity V is given as in 2 dimensional flow

  V=u i +v j

V=f(x,y)

u=f(x,y)

v=f(x,y)

Rotational ability ω given as

\omega =\dfrac{1}{2}\left (\dfrac{\partial v}{\partial x}-\dfrac{\partial u} {\partial x}\right)

If

ω=0 ,then flow will be  irrotational.

ω ≠0 ,then flow will be rotational.

So we can say that , ω will be zero every where for  irrotational  two dimensional flow .

5 0
3 years ago
Home safety and security is an _________<br><br> process. (7 Letters)<br><br> Answer
Bas_tet [7]

Electric

Answer

Explain

5 0
3 years ago
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