Answer: a) 0.948 b) 117.5µf
Explanation:
Given the load, a total of 2.4kw and 0.8pf
V= 120V, 60 Hz
P= 2.4 kw, cos θ= 80
P= S sin θ - (p/cos θ) sin θ
= P tan θ(cos^-1 (0.8)
=2.4 tan(36.87)= 1.8KVAR
S= 2.4 + j1. 8KVA
1 load absorbs 1.5 kW at 0.707 pf lagging
P= 1.5 kW, cos θ= 0.707 and θ=45 degree
Q= Ptan θ= tan 45°
Q=P=1.5kw
S1= 1.5 +1.5j KVA
S1 + S2= S
2.4+j1.8= 1.5+1.5j + S2
S2= 0.9 + 0.3j KVA
S2= 0.949= 18.43 °
Pf= cos(18.43°) = 0.948
b.) pf to 0.9, a capacitor is needed.
Pf = 0.9
Cos θ= 0.9
θ= 25.84 °
(WC) V^2= P (tan θ1 - tan θ2)
C= 2400 ( tan (36. 87°) - tan (25.84°)) /2 πf × 120^2
f=60, π=22/7
C= 117.5µf
Answer:
1. 
2. 
3. 
4. 
Explanation:
Feel free to give brainliest
Have a great day!
C it would be c because that has more and the others have less
Answer:
//Program was implemented using C++ Programming Language
// Comments are used for explanatory purpose
#include<iostream>
using namespace std;
unsigned int second_a(unsigned int n)
{
int r,sum=0,temp;
int first;
for(int i= 1; I<=n; i++)
{
first = n;
//Check if first digit is 3
// Remove last digit from number till only one digit is left
while(first >= 10)
{
first = first / 10;
}
if(first == 3) // if first digit is 3
{
//Check if n is palindrome
temp=n; // save the value of n in a temporary Variable
while(n>0)
{
r=n%10; //getting remainder
sum=(sum*10)+r;
n=n/10;
}
if(temp==sum)
cout<<n<<" is a palindrome";
else
cout<<n<<" is not a palindrome";
}
}
}
Explanation:
The above code segments is a functional program that checks if a number that starts with digit 3 is Palindromic or not.
The program was coded using C++ programming language.
The main method of the program is omitted.
Comments were used for explanatory purpose.
