Answer:
SELECT distinct VendorName FROM Vendors
WHERE VendorID IN (
SELECT VendorID FROM Invoices
)
Explanation:
Answer:
B - Poor
Explanation:
As you get higher up, There is less oxygen which causes the engine to create less power.
Same question idea but different values... I hope I helped you... Don't forget to put a heart mark
Answer:
(a) 561.12 W/ m² (b) 196.39 MW
Explanation:
Solution
(a) Determine the energy and power of the wave per unit area
The energy per unit are of the wave is defined as:
E = 1 /16ρgH²
= 1/16 * 1025 kg/ m3* 9.81 m/s² * (2.5 m )²
=3927. 83 J/m²
Thus,
The power of the wave per unit area is,
P = E/ t
= 3927. 83 J/m² / 7 s = 561.12 W/ m²
(b) The average and work power output of a wave power plant
W = E * л * A
= 3927. 83 J/m² * 0.35 * 1 *10^6 m²
= 1374.74 MJ
Then,
The power produced by the wave for one km²
P = P * л * A
= 5612.12 W/m² * 0.35 * 1* 10^6 m²
=196.39 MW
Answer: Kinetic energy
Explanation: If you live in a country other than UK you will probably call it something different
