Please help! timed test. This about electrical control. Please be serious.

Oil with a density of 850 kg/m3 and kinematic viscosity of 0.00062 m2/s is being discharged by an 8-mm-diameter, 42-m-long horiz

sladkih [1.3K]

Answer:

The flow rate of oil through the pipe is 1.513E-7 m³/s.

Explanation:

Given

Density, ρ = 850 kg/m³

Kinematic viscosity, v = 0.00062 m²/s

Diameter, d = 8-mm = 0.008m

Length of horizontal pipe, L = 42-m

Height, h = 4-m.

We'll solve the flow rate of oil through the pipe by using Hagen-Poiseuille equation.

This is given as

∆P = (128μLQ)/πD⁴

Where ∆P = Rate of change of pressure

μ = Dynamic Viscosity

Q = Flow rate of oil through the pipe.

First, we need to determine the dynamic viscosity and the rate of change in pressure

Dynamic Viscosity, μ = Density (ρ) * Kinematic viscosity (v)

μ = 850 kg/m³ * 0.00062 m²/s

μ = 0.527kg/ms

Then, we calculate the rate of change of pressure.

Assuming that the velocity through the pipe is so small;

∆P = Pressure at the bottom of the tank

∆P = Density (ρ) * Acceleration of gravity (g) * Height (h)

Taking g = 9.8m/s²

∆P = 850kg/m³ x 9.8m/s² x 4m

∆P = 33320N/m²

Recall that Hagen-Poiseuille equation.

∆P = (128μLQ)/πD⁴ --- Make Q the subject of formula

Q = (πD⁴P)/(128μL)

By substituton;

Q = (π * 0.008⁴ * 33320)/(128 * 0.527 * 42)

Q = 0.00000015133693643099

Q = 1.513E-7 m³/s.

Hence, the flow rate of oil through the pipe is 1.513E-7 m³/s.

8 0

3 years ago

The product of two factors is 4,500. If one of the factors is 90, which is the other factor?

natulia [17]

The other factor is 50
Hope this help <3
Help me and mark my answer as brainliest plz plz

8 0

3 years ago

Carbon dioxide contained in a piston–cylinder device is compressed from 0.3 to 0.1 m3. During the process, the pressure and volu

Lunna [17]

Answer:

$W = -6.5 Kpa m^6 (\frac{1}{0.1 m^3}- \frac{1}{0.3 m^3})= -6.5 Kpa m^6 (6.66 m^-3) =-43.33 Kpa m^3 = -43.33 KJ$

Explanation:

For this case we know the following info :

$V_i = 0.3 m^3$ represent the initial volume

$V_f = 0.1 m^3$ represent the final volume

We know that the pressure and volume are related with the following expression:

$P = aV^{-2}= \frac{a}{V^2}$

Where a is a constant given $a = 6.5 Kpa m^6$

And we need to calculate the work associated to this process.

We have a compression, and by definition the work is defined with the following general expression:

$W = \int_{V_i}^{V_f} P dV$

If we replace the expression for P we got:

$W = \int_{V_i}^{V_f} a V^{-2} dV$

If we integrate we got:

$W = -a (\frac{1}{V}) \Big|_{V_i}^{V_f}$

Using the fundamental theorem of calculus we have:

$W = -a (\frac{1}{V_f} -\frac{1}{V_i})$

And replacing the values we got:

$W = -6.5 Kpa m^6 (\frac{1}{0.1 m^3}- \frac{1}{0.3 m^3})= -6.5 Kpa m^6 (6.66 m^-3) =-43.33 Kpa m^3 = -43.33 KJ$

5 0

4 years ago

It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 610 MPa. Calc

julia-pushkina [17]

Answer:

volume fraction of fibers is 0.4

Explanation:

Given that for the aligned carbon fiber-epoxy matrix composite:

Diameter (D) = 0.029 mm

Length (L) = 2.3 mm

Tensile strength ( $\sigma_{cd}$ ) = 610 MPa

fracture strength ( $\sigma_f$ ) = 5300 MPa

matrix stress ( $\sigma_m$ ) = 17.3 MPa

fiber-matrix bond strength ( $\tau_c$ ) = 19 MPa

The critical length is given as:

$L_C=\sigma_f(\frac{D}{2\tau_c} )=5300*10^6(\frac{0.029*10^{-3}}{19*10^6} )=8.1*10^{-3}=8.1mm$

Since the critical length is greater than the length, the aligned carbon fiber-epoxy matrix composite can be produced.

The longitudinal strength is given by:

$\sigma_{cd}=\frac{L*\tau_c}{D} .V_f+\sigma_m(1-V_f)$

making Vf the subject of the formula:

$V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}$

Vf is the volume fraction of fibers.

Therefore:

$V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}=\frac{610*10^6-17.3*10^6}{\frac{2.3*10^{-3}*19*10^6}{0.029*10^{-3}}-17.3*10^6} } =0.4$

volume fraction of fibers is 0.4

8 0

3 years ago

Help me on this questions?

VMariaS [17]

Answer:

1)f

thats all i know sorry ;-;

4 0

3 years ago

Read 2 more answers