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stepan [7]
3 years ago
15

Please help! timed test. This about electrical control. Please be serious.

Engineering
1 answer:
Lapatulllka [165]3 years ago
3 0
The answer is memory i believe
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The water in a large lake is to be used to generate electricity by the installation of a hydraulic turbine-generator at a locati
Lynna [10]

Answer:

a) 0.76

b) 0.80

c) 1964 kW

Explanation:

GIVEN DATA:

\dot m = 5000 kg/s

Assume Mechanical energy at exist is negligible

A) Take lake bottom as reference, and then kinetic and potential energy  are taken as zero.

change in mechanical energy is givrn as

e_{in} - e_{out} = \frac{P}{\rho} - 0 = gh = 9.81 \times 50( \frac{1 kJ/kg}{1000 m^2/s^2}

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B) \eta -{gen} = \frac{\eta_{overall}}{\eta_{gen}} = \frac{0.76}{0.95} = 0.80

c) \dot W_{shaft} = \eta_{overall} \left | \Delta \dot E_{mec} \right | = 0.80(2455)

\dot W_{shaft} = 1964 kW

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4 years ago
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Explanation:

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3 years ago
I’m bored let’s text
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Answer:

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<em>안녕하세요 모두가 잘되기를 바랍니다. 안전 유지</em>

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Read 2 more answers
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