Answer:
the correct answer to your question is 20
Answer:
a - the position of equilibrium lies far to the right, with products being favored.
Explanation:
117 mL of 0.210 M K₂S solution
Explanation:
The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).
We have the chemical reaction:
K₂S + Co(NO₃)₂ → CoS + 2 KNO₃
molar concentration = number of moles / volume (L)
number of moles = molar concentration × volume
number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles
We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.
volume = number of moles / molar concentration
volume of K₂S solution = 24.5 / 0.210 = 117 mL
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molar concentration
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Answer:
The answer to your question is the letter D. 12
Explanation:
Unbalanced chemical reaction
Al(OH)₃ + H₂SO₄ ⇒ Al₂(SO₄)₃ + H₂O
Reactants Elements Products
1 Al 2
1 S 3
5 H 2
7 O 13
Balanced chemical reaction
2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O
Reactants Elements Products
2 Al 2
3 S 3
12 H 12
18 O 18
Sum up the coefficients
Result = 2 + 3 + 1 + 6
= 12
Answer:- 537 kJ of heat is released.
Solution:- For the given equation,
is -657 kJ and the coefficient of
in the balanced equation is 2. It means 657 kJ of heat is released when 2 moles of chlorine are used. We need to calculate the heat released when 116 g of
are used.
Grams of chlorine are converted to moles and then multiplied by the
value and divided by the coefficient of chlorine and the set could be shown using dimensional analysis as:

= 537.46 kJ
If we use the correct sig figs then it needs to be round off to three sig figs as the given grams of chlorine has only three sig figs. So, 537 kJ of heat is released.