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marishachu [46]
3 years ago
11

What happens that causes many leaves to change color in the autumn

Chemistry
2 answers:
Alex_Xolod [135]3 years ago
7 0
The pigment that turns leaves green is chlorophyll. when chlorophyll leaves the leaves the leaf will turn different colors<span />
motikmotik3 years ago
4 0
Hi there, Aishapatel!
Leaves have a substance called Chlorophyll in them, which makes them green. As summer turns to winter, it gets cold and the leaves die. As the leaves die, the chlorophyll goes away, the leaf begins to change color.
I hope I helped!
(P.S. Brainliest Answer please? I got to Virtuoso but Brainly just removed it and I don't know why, but now I have to start over. :()
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What is the mass of 0.257 mol of calcium nitrate?
poizon [28]

Answer: 42.14 g

Explanation:      calcium nitrate -  Ca(NO_{3} )_{2}

                   , the molar mass of calcium nitrate = 164 g

<h3>                   formula used = given mass/molar mass= no of moles </h3>

                   mass required =0.257*164

                                               =42.14 g

                     

             

4 0
1 year ago
PLEASE HELP MEEE!!!!
Assoli18 [71]
It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
3 0
3 years ago
The missing components in the table to the right
Fed [463]

The missing components in the table to the right are indicated with orange letters. Use the periodic table in the tools bar and this link Web Elements to fill in the corresponding values. A B C D E F G. 2. See answers. Log in to add ... F = 737.7kJ/mol. G = 495.8kJ/mol. Explanation: We are asked some of the ...

2 answers

4 0
3 years ago
You are given a solid that is a mixture of na2so4 and k2so4.
Murljashka [212]

Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

(Na)₂SO₄=2Na⁺ +  SO_{4}^{2-}

Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of SO_{4}^{2-} ion is present.        

5 0
3 years ago
( urgent help needed!! 50pts + brainliest )
Ivanshal [37]

Answer:

Thorium-234 option a .......

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