Answer:
1) Dispersion forces: It is a type of force which is present between atoms and molecules. It is a weakest intermolecular force that occurs between atoms. It is also called induced dipole-induced dipole attraction.
2. Dipole-dipole: It is a type of attractive force which is present between the negative end of one molecule with the positive end of another molecule. This type of attractive force occurs between polar molecules.
3) Hydrogen bond: It is a type of electromagnetic force which is present between hydrogen and high electronegative atoms such as nitrogen and oxygen etc.
Answer:


Explanation:
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In this case, the undergoing chemical reaction is:

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:


Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

Finally, the Gibbs free energy for the reaction at 298.15K is:

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The mole fraction of ethanol c2h5oh in an aqueous solution that is 46 percent ethanol by mass is 0.25
Mole fraction is the mole of one of the component of the solution divided by the total moles of the solution
Calculating the mole fraction of ethanol,we get
Percentage by weight of ethyl alcohol is 46% which implies in 100 g of this solution is 46 g while the mass of the water will be 54% of 100 g = 54g.
Finding the moles of water and the ethyl alcohol {molar mass of water(H₂O) = 18 and molar mass of ethyl alcohol(C₂H₆O = 46}
Moles = mass/molar mass
moles of ethanol = 46/46 = 1
moles of water = 54/18 = 3
ntotal=1+3=4
Mole fraction of ethanol is:
Mole of ethanol = 1/4
Total mole of solution
Hence, the mole fraction is 1/4 or 0.25
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