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3 years ago

What is the correct balanced equation for the following:

1 answer:

5 0

A)
K has a positive charge of 1
I has a negative charge of 1
S has a negative charge of 2
Pb has a positive charge of 2

2KI + PbS —> PbI2 + K2S

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How many Chorine atoms should bond with one Aluminum atom?

White raven [17]

Answer:

three chlorine atoms

Explanation:

8 0

2 years ago

Read 2 more answers

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago

How many grams of Mg(NO3)2 would be produced? please show how you got the answer

Len [333]

Answer:

148 grams of relative atomic mass

Explanation:

magnesium atomic mass : 24

nitrogen : 14

oxygen : 16

24 × 1

14 × 1 × 2

16 × 3 × 2

24 + 28 + 80 = 148 grams

7 0

3 years ago

Convert 3.09 x 10~3 m = nm

Dmitriy789 [7]

3090000000nm

since there's 1m = 1000000000nm

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3 years ago

H2S what species are present at 10-6 mol/L or greater when dissolved in water

Anastaziya [24]

Answer:

the answer has been given below have a good day

Explanation:

mark as brainiest

5 0

2 years ago