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Afina-wow [57]
3 years ago
11

What is the correct balanced equation for the following:

Chemistry
1 answer:
Romashka [77]3 years ago
5 0
A)
K has a positive charge of 1
I has a negative charge of 1
S has a negative charge of 2
Pb has a positive charge of 2

2KI + PbS —> PbI2 + K2S
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Lewis structure for nitrogen triiodide, NI(3)
Rasek [7]

Answer:

Lewis structure for nitrogen triiodide,NI_3 is given in the attachment.

Explanation:

Given:

The given compound is Nitrogen triiodide. In which 1 atom of Nitrogen combines with 3 atoms of Iodine. Both Nitrogen and Iodine are non-metals,So they form covalent bond by sharing of electrons.

The electron configuration of Nitrogen and Iodine is given below;

N(7) = 1s^2,2s^22p^3\\I(53) = 1s^2,2s^22p^6,3s^23p^63d^{10},4s^24p^64d^{10},5s^25p^5

There are 5 electrons in valance shell of Nitrogen atom and 7 electrons in valance shell of Iodine atom.

So, 3 atom of Iodine shares 1 electron with 1 electrons of Nitrogen.

The Lewis dot Structure is in the attachment.

3 0
3 years ago
Explica brevemente cuidado del aparato digestivo ​
kirill115 [55]

Answer:

For better digestive health, follow these simple tips:

Eat a high-fiber diet. ...

Be sure you're getting both soluble and insoluble fiber. ...

Minimize your intake of foods high in fat. ...

Select lean meats. ...

Add probiotics to your diet. ...

Follow a regular eating schedule. ...

Drink plenty of water.

Explanation:

6 0
3 years ago
Jen makes a Venn diagram to compare active transport and passive transport.
Oksanka [162]

Answer:

moves molecules

Explanation:

I did this one yesterday! Active transport moves low to high concentration and passive does the opposite so C and D are not an option. Active transport requires energy and Passive Transport does not so it has to be A.!

6 0
3 years ago
Read 2 more answers
Identify the class of the 8 organic compound below (alcohol, carboxylic acid, halocarbon, alcohol, ketone, ester, ether). Some w
Darina [25.2K]

Answer:

See below ~

Explanation:

1) <u>Ketone</u>

2) <u>Carboxylic Acid</u>

3) <u>Ketone</u>

4) <u>Ether</u>

5) <u>Alcohol</u>

6) <u>Halocarbon</u>

7) <u>Ester</u>

8) <u>Ketone</u>

4 0
2 years ago
In Part A, you found the number of moles of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxyge
n200080 [17]

Answer:

1.40 moles.

Explanation:

The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -

4P + 5O_2 = 2P_2O_5

In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 4 moles of P

So, for 1.8 moles of  P_2O_5 amount of required moles of P = \frac{4}{2} \times 1.80 = 3.60

In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 5 moles of oxygen

So, for 1.40 moles of P_2O_5 moles of O_2 required = \frac{5}{2} \times 1.40 = 3.50

Thus as of now we have 3.60 moles of P_2O_5 and 3.50 moles of O_2.

As in the reaction of formation of P_2O_5, oxygen is the limiting reagent.

So the moles of P_2O_5 formed by the 3.50 moles of oxygen will be

P_2O_5 = \frac{2}{5} \times 3.50 = 1.40 moles.

5 0
3 years ago
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