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Rus_ich [418]
3 years ago
5

Calculate the work engergy gained or lost by the system when a gas expands from 35 to 55 l against a constant external presure o

f 3atm.
Chemistry
1 answer:
Mariana [72]3 years ago
6 0

Answer:  The work energy lost by the system is -6078 Joules

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=-P\Delta V  {Work is done by the system as the final volume is greater than initial volume and is negative}

where P = pressure = 3 atm

\Delta V = change in volume = (55-35) L = 20 L

w =-3atm\times (20)L=-60Latm=-6078Joules  

{1Latm=101.3J}

Thus work energy lost by the system is -6078 Joules

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a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
A chemical equation that does not indicate relative amounts of reactants and products is called
Zielflug [23.3K]

Answer:

The correct answer is skeleton equation.

Explanation:

In chemistry, the skeletal formula of a compound is an abbreviated representation of its molecular structure. Skeleton formulas are used because they clearly show complicated structures, they are fast and simple to draw.

All atoms that are not carbon or hydrogen are represented by their chemical symbol. The relative amounts of reagents and products are not indicated.

Have a nice day!

6 0
3 years ago
How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?
Montano1993 [528]

Answer:

2.0202 grams

Explanation:

1.4% (m/v) glucose solution means: 1.4g glucose/100mL solution.

so ?g glucose = 144.3 mL soln

Now apply the conversion factor, and you have:

?g glucose = 144.3mL soln x (1.4g glucose/100mL soln).

so you have (144.3x1.4/100) g glucose= 2.0202 grams

6 0
3 years ago
Read 2 more answers
Which of these elements is the most reactive
mr_godi [17]

Answer:

What elements?

Explanation:

The alkali metals are softer than most other metals. Cesium and francium are the most reactive elements in this group. Alkali metals can explode if they are exposed to water.

Not sure if this what you were talking about but here

This from google btw not gonna lie

7 0
3 years ago
In an electron dot diagram what is the maximum number of dot surrounding a symbol. A. 8 B.4 C. 2 D.10
Ksju [112]

Answer:

A. 8

Explanation:

8 valence electrons means you have a full shell.

4 0
3 years ago
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