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Rus_ich [418]
2 years ago
5

Calculate the work engergy gained or lost by the system when a gas expands from 35 to 55 l against a constant external presure o

f 3atm.
Chemistry
1 answer:
Mariana [72]2 years ago
6 0

Answer:  The work energy lost by the system is -6078 Joules

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=-P\Delta V  {Work is done by the system as the final volume is greater than initial volume and is negative}

where P = pressure = 3 atm

\Delta V = change in volume = (55-35) L = 20 L

w =-3atm\times (20)L=-60Latm=-6078Joules  

{1Latm=101.3J}

Thus work energy lost by the system is -6078 Joules

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What is the ph value of the produced solution when hcl reacts with naoh ?
algol13

Answer:

The answer to your question is: 7

Explanation:

The reaction between HCl and NaOH is a neutralization reaction, that means that the products will be water and a salt and the pH will be 7.

                     HCl + NaOH  ⇒  NaCl + H₂O

4 0
3 years ago
Which two characteristics describe all animals
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All animals can be dangerous and they would fight for their family. (This might be wrong)

5 0
2 years ago
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Marta_Voda [28]

Answer:

proton. neutrons and electrons

5 0
2 years ago
The picture shows a contractile vacuole of a unicellular freshwater organism. The contractile vacuole regulates the flow of wate
yuradex [85]

Answer:

A.The concentration of water is greater outside the cell than inside the cell.

Explanation:

The contractile vacuole of certain organisms functions to regulate water flow in and out of the cell. It does this by storing excess water that comes into the cell. In the case of this organism with a filled up contractile vacuole, it means water is flowing into the cell.

Naturally, water will flow into a living cell when an osmotic gradient i.e. difference in concemtration, has been created between intracellular and extracellular solutions. Osmosis involves movement of substances from a region of high water concentration to a region of low water concentration. This means that if water is flowing into the cell, which is stored by the contractile vacuole, the concentration of water must be greater outside the cell than inside.

6 0
2 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
2 years ago
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