Calculate the work engergy gained or lost by the system when a gas expands from 35 to 55 l against a constant external presure o

Question

2 years ago

5

f 3atm.

1 answer:

Mariana [72] · Answer 1 · 2022-09-17T01:06:38+03:00

Answer: The work energy lost by the system is -6078 Joules

Explanation:

According to first law of thermodynamics:

$\Delta E=q+w$

$\Delta E$ =Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system= $-P\Delta V$ {Work is done by the system as the final volume is greater than initial volume and is negative}

where P = pressure = 3 atm

$\Delta V$ = change in volume = (55-35) L = 20 L

w = $-3atm\times (20)L=-60Latm=-6078Joules$

{1Latm=101.3J}

Thus work energy lost by the system is -6078 Joules