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Rus_ich [418]
2 years ago
5

Calculate the work engergy gained or lost by the system when a gas expands from 35 to 55 l against a constant external presure o

f 3atm.
Chemistry
1 answer:
Mariana [72]2 years ago
6 0

Answer:  The work energy lost by the system is -6078 Joules

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system=-P\Delta V  {Work is done by the system as the final volume is greater than initial volume and is negative}

where P = pressure = 3 atm

\Delta V = change in volume = (55-35) L = 20 L

w =-3atm\times (20)L=-60Latm=-6078Joules  

{1Latm=101.3J}

Thus work energy lost by the system is -6078 Joules

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