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poizon [28]
3 years ago
15

give the chemical composition of the followings : Name Chemical Composition Coal gas Water gas Producer gas Natural gas

Chemistry
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

Below.

Explanation:

Coal gas is a mixture of a variety of gases: inflammable gases including, hydrogen, methane, ethylene, carbon monoxide and volatile hydrocarbons and small amounts of non flammable gases like nitrogen and carbon dioxide.

Water gas consists mainly of carbon monoxide and hydrogen.

Producer gas is similar to water gas and consists mainly of carbon monoxide and hydrogen together with nitrogen and carbon dioxide.

Natural gas occurs naturally and consists mainly of methane with small amounts of other hydrocarbon gases.

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allochka39001 [22]

Answer:

They are eukaryotic, which means they have a nucleus. Most have mitochondria

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2 years ago
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BlackZzzverrR [31]

Explanation:

Metals -

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5 0
3 years ago
What is the net ionic equation for a reaction between HCl and NaOH
kodGreya [7K]

Answer:

What is the net ionic equation for a reaction between HCl and NaOH?

Explanation:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl

Hope that helped.

5 0
2 years ago
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Natasha_Volkova [10]

D is the correct answer......

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4 0
2 years ago
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What is the boiling point of a solution containing 203 g of ethylene glycol (C2H6O2) and 1035 g of water? (Kb for water is 0.52
Andru [333]

Answer:

101,37°C

Explanation:

Boiling point elevation is one of the colligative properties of matter. The formula is:

ΔT = kb×m <em>(1)</em>

Where:

ΔT is change in boiling point: (X-100°C) -X is the boiling point of the solution-

kb is ebulloscopic constant (0,52°C/m)

And m is molality of solution (mol of ethylene glycol / kg of solution). Moles of ethylene glycol (MW: 62,07g/mol):

203g × (1mol /62,07g) = <em>3,27moles of ethlyene glycol</em>

<em />

Molality is: 3,27moles of ethlyene glycol / (1,035kg + 0,203kg) = 2,64m

Replacing these values in (1):

X - 100°C = 0,52°C/m×2,64m

X - 100°C = 1,37°C

<em>X = 101,37°C</em>

<em></em>

I hope it helps!

7 0
3 years ago
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