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svp [43]
3 years ago
14

According to Le

Chemistry
2 answers:
katrin [286]3 years ago
5 0

Shift it toward the side with lower total mole concentration.

____ [38]3 years ago
4 0

Answer:

Shift it toward the reactants.

Explanation:

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Considering that the mantle is 44.8% oxygen and 21.5% silicon by mass, calculate the mole ratio of oxygen atoms to silicon atoms
horrorfan [7]

The mantle has a mass of around 4.278 X 10 ^2^4 kg that is around 68.4% of earth's mass.

So to calculate moles we need to first find out the mass of oxygen and silicon present in mantle. It is given that oxygen is 44.8% by mass in mantle and 21.5% by mass in mantle, therefore to calculate its mass, we need to use \text{mass percentage }=\frac{\text{mole of solute}}{\text{mass of solution}}\times100

Now, to calculate mass percentage of oxygen

44.8 =\frac{x}{4.278X10^2^4kg}\times100

x= 191.65\times10^2^2kg

Similarly the mass of silicon can be calculated

21.5 =\frac{x}{4.278X10^2^4kg}\times100

x=91.977\times10^2^2kg

Now, the moles of any substance is calculated by

\text{moles}= \frac{\text{given mass}}{\text{molar mass}}

\text{moles of oxygen}= \frac{191.65\times10^2^2kg}{2.6566962\times10^-^2^6kg}

where, mass of oxygen in kilograms is 2.6566962\times10^-^2^6kg

So,\text{moles of oxygen}=72.1384\times10^4^8\text{moles of O}

Similarly \text{moles of silicon}= \frac{91.977\times10^2^2kg}{4.663\times10^-^2^6kg}

\text{moles of silicon}=19.724\times10^4^8\text{moles of Si}

Now, to calculate mole ratio we need to divide every moles to the lowest calculated mole that is the moles of Si and round it off to the nearest whole number.

\text{mole ratio of oxygen}= \frac{72.138\times10^4^8kg}{19.724\times10^4^8kg}

=3.65\approx 4

\text{mole ratio of Silicon}=\frac{19.724\times10^4^8}{19.724\times10^4^8}

=1

\text{Mole ratio of Oxygen : Mole ratio of Silicon} = 4:1


6 0
4 years ago
Read 2 more answers
What is the net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH?
Lesechka [4]
<span>The net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH is </span>the solid AlOH3  formed.
7 0
4 years ago
What is the main basis for the classification system they chose?
VARVARA [1.3K]
What classification system????
3 0
4 years ago
How many quarts of pure antifreeze must be added to 5 quarts of a 20 ntifreeze solution to obtain a 50 ntifreeze solution?
Ede4ka [16]

Quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution is 3.

Antifreeze solution is a solute that lowers the freezing point of the liquid in a solution.

For calculating the amount of quarts of pure antifreeze solution added can be given by:

5×20/100 + x × 100% = (x+5) × 50/100

Where, x is the amount of antifreeze required for addition and pure antifreeze is 100% of the antifreeze taken.

1 + x = (x+5) 0.5

1 + x = 0.5x + 2.5

0.5x = 1.5

x = 3

So, 3 quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution.

Learn more about Antifreeze solution here, brainly.com/question/14619701

#SPJ4

5 0
2 years ago
What is the molar mass of KCI
9966 [12]

Answer:

178.01347 ± 0.00093 g/mol

Explanation:

7 0
3 years ago
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