Answer:
tama yon sagot nya gayahin mo nalang
Answer:
17.6
Explanation:
Answer is explained above
Explanation:
1 literThe total of water is equal to 1000.0 g of water
we need to find the molality of a solution containing 10.0 g of dissolved in Na₂S0₄1000.0 g of water
1. For that find the molar mass
Na: 2 x 22.99= 45.98
S: 32.07
O: 4 x 16= 64
The total molar mass is 142.05
We have to find the number of moles, y
To find the number of moles divide 10.0g by 142.05 g/mol.
So the number of moles is 0.0704 moles.
For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.
The molarity would end up being 0.0704 M
The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is 0.0704 Mliter
The volume of a 6.67 m nacl solution
that contains 3.12 mol nacl is 0.468.
You just need to follow this formula:
C = n / V
So, it will be
V = n / C
<span> = 3.12 / 6.67 moles / Liter </span>
<span> = 0.468 L</span>
The correct answer is D :)
