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alexgriva [62]
4 years ago
13

You start with 12.94 g sample of a mixture containing SiO2, NaCl, and NH4Cl. If after subliming

Chemistry
1 answer:
Tema [17]4 years ago
8 0
<h3>Answer:</h3>

83.23 %

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the sample mixture is 12.94 g
  • Mass of the remaining mixture after sublimation is 2.17 g

We are required to get the mass percent of NH₄Cl in the original sample

<h3>Step 1 : Calculate mass of NH₄Cl in the original sample;</h3>

Mass of NH₄Cl = Total mass of the mixture - remaining mass after sublimation

                         = 12.94 g - 2.17 g

                          = 10.77 g

<h3>Step 2: Percent by mass of NH₄Cl in the original sample</h3>

% of NH₄Cl by mass =(Mass of NH₄Cl÷Total mass of original sample)×100

                                  = (10.77 g ÷ 12.94 g) × 100

                                  = 83.23 %

Therefore, the percent by mass of NH₄Cl in the original sample is 83.23%

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The chemical formula of ordinary sugar is C12H22O11. Calculate the mass of 7.35 mol of sugar.
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