Question

What is the concentration of the acid in this titration 1.2 m 2.4 m 1.95 m 0.98 m 1.98 m

Answer 1

Answer:

1.95

Explanation:

Just did the test and it was correct!

Answer 2

Answer: The correct answer is 1.95 M

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of unknown acid which is HCl.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=?M\\V_1=(45.5-0.0)=45.5mL\\n_2=2\\M_2=1.2M\\V_2=(37.5-0.5)=37mL$

Putting values in above equation, we get:

$1\times M_1\times 45.5=2\times 1.2\times 37\\\\M_1=1.95M$

Hence, the concentration of unknown HCl solution comes out to be 1.95 M.