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3 years ago

F-orbital can accommodate maximum of... electron?

Chemistry

2 answers:

MAVERICK [17]3 years ago

7 0

Explanation:

S= 2

P=6

D=10

F= 14

F orbital holds a maximum of 14 electrons

kodGreya [7K]3 years ago

3 0

Answer:

14.

Explanation:

The f level consists of 7 orbitals and each can accommodate up to 2 electrons.

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what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro

Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

$\tt vf-vo=8-4=4~m/s$

Acceleration = ratio of a change in velocity and the time

$\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}$

Input the value :

$\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2$

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2 years ago

Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the

Olin [163]

Firstly we need to determine the partial pressure of O2:

$\begin{gathered} P_{O_2}=X\times P_T \\ P_{O_2}:partial\text{ }pressure \\ X:mole\text{ }fraction \\ P_T:total\text{ }pressure \\ \\ P_{O_2}=0.209\times0.35\text{ }atm \\ P_{O_2}=0.073\text{ }atm \end{gathered}$

We will now use the Henry's Law equation to determine the solubility of the gas:

$\begin{gathered} c=K_H\times P_{O_2} \\ c:solubility\text{ }or\text{ }concentration\text{ }of\text{ }the\text{ }gas(M) \\ K_H:Henry^{\prime}sLawconstant=3.7\times10^{-2}M\text{ }atm^{-1} \\ P_{O_2}:partial\text{ }pressure\text{ }of\text{ }the\text{ }gas=0.073atm \\ \\ c=3.7\times10^{-2}M\text{ }atm^{-1}\times0.073 \\ c=2.7\times10^{-3}M \end{gathered}$

Answer: Solubility is 2.7x10^-3 M

6 0

7 months ago

An aqueous solution of calcium hydroxide is standardized by titration with a 0.120 M solution of hydrobromic acid. If 16.5 mL of

Artist 52 [7]

<u>Answer:</u> The molarity of calcium hydroxide in the solution is 0.1 M

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$