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sesenic [268]
3 years ago
5

How many hydrogen atoms are in an acyclic alkane with 8 carbon atoms?

Chemistry
1 answer:
vfiekz [6]3 years ago
7 0
The general formula of acyclic alkane is CnH2n+2. 

<span>When n = 8 : </span>
<span>Number of hydrogen atoms = 2n + 2 = 18</span>
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Barium nitrate has the formula Ba( NO3)2. Which statement is true about barium nitrate?
OLga [1]
I found these four statements for that question:

Each molecule contains four different elements.

Each molecule contains three atoms.

Each molecule contains seven different bonds.

Each molecule contains six oxygen atoms.

The last one is true. Each molecule contains six oxygen atoms.
The number to the right of O and of (NO3) ares subscripts.


The chemical formula uses subscripts to indicate the number of atoms.



The subscript 2 in (NO3)2 means that there are two NO3 radicals.


And the subscript 3 to the right of O means that each NO3 radical has three atoms of O.

Then, the number of atoms of O is 2 * 3 = 6.


So, the true statement is the last one: each molecule of Ba (NO3)2 has six atoms of O.


From that molecule you can also tell:

- Each molecule contains one atom of barium

- Each molecule contains two atoms of nitrogen

- Each molecule contains two NO3 radicals

4 0
3 years ago
C.) Is heating of cobalt (ii) chloride crystals a chemical change or a physical change (Imk)​
miv72 [106K]

Answer: Heating the hydrated forms of cobalt chloride reverses the reactions above, returning cobalt chloride to the blue, water-free, or anhydrous, state. Water is "liberated" in these reactions, known as dehydration reactions.

Explanation:

8 0
3 years ago
What must happen in a chemical reaction?
klasskru [66]
The anwser is atoms are destroyed
6 0
3 years ago
What would the total mass of a 4.9 mole sample of Barium (Ba) be if its Molar Mass is 137g?
Aleksandr-060686 [28]

Answer:

m = 671 grams

Explanation:

Given that,

No of moles, n = 4.9

Molar mass of Barium, M = 137 g

Mass divided by molar mass is equal to no of moles. It can be given by the formula as follows :

n=\dfrac{m}{M}\\\\m=n\times M\\\\m=4.9\times 137\\\\m=671.3\ g

or

m = 671 grams

So, the total mass of the sample of Barium is 671 grams.

8 0
3 years ago
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Anna007 [38]
B. Drought. Hope that helped
5 0
3 years ago
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