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boyakko [2]
3 years ago
14

A long, straight wire lies in the plane of a circular coil with a radius of 0.018 m. the wire carries a current of 5.6 a and is

placed along a diameter of the coil. (a) what is the net flux through the coil? (b) if the wire passes through the center of the coil and is perpendicular to the plane of the coil, find the net flux through the coil.
Physics
1 answer:
iris [78.8K]3 years ago
5 0
(a) The net flux through the coil is zero.
In fact, the magnetic field generated by the wire forms concentric circles around the wire. The wire is placed along the diameter of the coil, so we can imagine as it divides the  coil into two emisphere. Therefore, the magnetic field of the wire is perpendicular to the plane of the coil, but the direction of the field is opposite in the two emispheres. Since the two emispheres have same area, then the magnetic fluxes in the two emispheres are equal but opposite in sign, and so they cancel out when summing them together to find the net flux.

(b) If the wire passes through the center of the coil but it is perpendicular to the plane of the wire, the net flux through the coil is still zero.
In fact, the magnetic field generated by the wire forms concentric lines around the wire, so it is parallel to the plane of the coil. But the flux is equal to
\Phi = BA \cos \theta
where \theta is the angle between the direction of the magnetic field and the perpendicular to the plane of the coil, so in this case \theta=90^{\circ} and so the cosine is zero, therefore the net flux is zero.
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Reika [66]

Answer:

The magnitude of the resultant decreases from A+B to A-B

Explanation:

The magnitude of the resultant of two vectors is given by

R=\sqrt{A^2 +B^2 +2AB cos \theta}

where

A is the magnitude of the first vector

B is the magnitude of the second vector

\theta is the angle between the directions of the two vectors

In the formula, A and B are constant, so the behaviour depends only on the function cos \theta. The value of cos \theta are:

- 1 (maximum) when the angle is 0, so the magnitude of the resultant in this case is

R=\sqrt{A^2 +B^2+2AB}=\sqrt{(A+B)^2}=A+B

- then it decreases, until it becomes 0 when the angle is 90 degrees, where the magnitude of the resultant is

R=\sqrt{A^2 +B^2+0}=\sqrt{A^2+B^2}

- then it becomes negative, and continues to decrease, until it reaches a value of -1 when the angle is 180 degrees, and the magnitude of the resultant is

R=\sqrt{A^2 +B^2-2AB}=\sqrt{(A-B)^2}=A-B


4 0
3 years ago
A(n) 0.2 kg object is swung in a vertical circular path on a string 0.1 m long. The acceleration of gravity is 9.8 m/s2 . If a c
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Answer:

T=83.37N

Explanation:

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\sum F_y: T-mg=F_c

Where F_c is the centripetal force and is given by:

F_c=ma_c=m\frac{v^2}{r}

Replacing and solving for T:

T=m\frac{v^2}{r}+mg\\T=0.2kg\frac{(6.38\frac{m}{s})^2}{0.1m}+0.2kg(9.8\frac{m}{s^2})\\T=83.37N

8 0
4 years ago
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barxatty [35]

The magnet (south pole of the magnet) has magnetized the right side of the block.

<h3>Direction of electric field in the magnetic material</h3>

The direction of electric field of the atom of the magnetic material is unpolarized.

From the diagram in the image, the right hand side of the magnetic material is being attracted to south pole of the magnet.

Thus, we can conclude that, the magnet has magnetized the right side of the block.

Learn more about magnetic material here: brainly.com/question/22074447

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7 0
2 years ago
A mountaintop is a height y above the level ground. A woman measures the angle of elevation of the
Kamila [148]
Refer to the diagram shown below.
We want to find y in terms of d, φ and θ.

By definition,
tan (\theta) =  \frac{y}{x} \\\\ tan( \phi) = \frac{y}{x-d}

Therefore
y = x tan(θ)                   (1)
y = (x - d) tan(φ)           (2)

Equate (1) and (2).
(x - d) \, tan(\phi) = x \, tan(\theta) \\ x[tan(\phi) - tan(\theta)] = d \, tan(\phi) \\ x= \frac{d tan(\phi)}{tan(\phi)-tan(\theta)}

From (1), obtain the required expression for y.

Answer:
y= \frac{d \, tan(\phi) \, tan(\theta)}{tan(\phi)-tan(\theta)}

7 0
3 years ago
A single sports fan is capable of yelling at an intensity level of 80 dB from a given distance. If 10,000 similar fans were all
riadik2000 [5.3K]

Answer: option "A" is correct

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4 0
3 years ago
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