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3 years ago

What causes these H-bonds to form?

1 answer:

4 0

Answer: It is caused by the tendency of some atoms in molecules to attract electrons more than their accompanying atom.

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Copper crystallizes in a face-centered cubic lattice (the Cu atoms are at the lattice points and at the face centers). If the de

Delvig [45]

Answer:

The unit cell edge lenght in pm is equal to 361 pm

Explanation:

Data provided:

ρ=Copper density=8.96 g/cm3

Atomic mass of copper=63.54 g/mol

Atoms/cell=4 atoms (in theory)

Avogadro's number=6.02x $10^{23}$ atoms/mol

Since copper has a cubic structure, its cell volume is equal to $a^{3}$ , which can be obtained through the relationship:

cell volume= $\frac{(atoms/cell)(atomic mass)}{(density)(Avogadros number)}$

Substituting the values:

cell volume= $\frac{(4 atoms)(63.54 g/mol)}{(8.96 g/cm3)(6.02x10^{23}) }=4.71x10^{-23}cm^{3}$

clearing, we have:

a= $\sqrt[3]{4.71x10^{-23}cm^{3} }=3.61x10^{-8}cm$

We convert from centimeter to picometer, 1cm=1x $10^{10}$ pm

a= $3.61x10^{-8}cmx\frac{1x10^{10}pm }{1cm} =361 pm$

8 0

3 years ago

Someone plsss help me I will make you as brain plsss

Helga [31]

Answer:

2 only

Explanation:

Hope this helps

6 0

3 years ago

Read 2 more answers

A first-order reaction (A → B) has a half-life of 25 minutes. If the initial concentration of A is 0.900 M, what is the concentr

Oksanka [162]

Answer:

0.6749 M is the concentration of B after 50 minutes.

Explanation:

A → B

Half life of the reaction = $t_{1/2}=25 minutes$

Rate constant of the reaction = k

For first order reaction, half life and half life are related by:

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{25 min}=0.02772 min^{-1}$

Initial concentration of A = $[A]_o=0.900 M$

Final concentration of A after 50 minutes = $[A]=?$

t = 50 minute

$[A]=[A]_o\times e^{-kt}$

$[A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}$

[A] = 0.2251 M

The concentration of A after 50 minutes = 0.2251 M

The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M

0.6749 M is the concentration of B after 50 minutes.

7 0

3 years ago

If there are 3.10 moles of O, how many moles of each of the compounds are present?

Burka [1]

Explanation:

The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.

H2SO4

1 mol of H2SO4 contains 4 mol of O

x mol of H2SO4 would contain 3.10 mol of O

x = 3.10 * 1 / 4 = 0.775 mol of H2SO4

C2H4O2

1 mol of C2H4O2 contains 2 mol of O

x mol of C2H4O2 would contain 3.10 mol of O

x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2

NaOH

1 mol of NaOH contains 1 mol of O

x mol of NaOH would contain 3.10 mol of O

x = 3.10 * 1 / 1 = 3.10 mol of NaOH

3 0

3 years ago

Which of these is a mechanism that could lead to a climate tipping point?

LuckyWell [14K]

Answer:

all th eabove i had this pls give brainliest i got this correct of of edmentum

Explanation:

5 0

3 years ago