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3 years ago

15

What causes these H-bonds to form?

1 answer:

erik [133]3 years ago

4 0

Answer: It is caused by the tendency of some atoms in molecules to attract electrons more than their accompanying atom.

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What stresses will shift the reaction to increase the products

AveGali [126]

Answer:

Change in molarity, temperature, volume/pressure depending on the conditions given

Explanation:

It really depends on the type of a reaction, however, we may apply general trends and see every possibility:

if we increase the concentration of products, then, according to the principle of Le Chatelier, the equilibrium will shift toward the formation of products;
if we have an endothermic reaction, increasing heat will lead a shift to the right and toward formation of products, since heat might be considered a reactant as well;
if we have an exothermic reaction, removing heat/decreasing temperature will lead to an increase in products, as we're removing one of our products, heat, and system will try to rebuild the amount of heat lost forming the other products as a result as well;
if we have gaseous substances in a reaction, an increase in pressure will shift the equilibrium to the right if we have a greater amount in moles of reactant gases compared to products, this is also known as a decrease in volume;
if we have gaseous substances in a reaction, a decrease in pressure will shift the equilibrium to the right if we have a greater amount in moles of product gases compared to reactants, this is also known as an increase in volume.

7 0

2 years ago

450 grams of gasoline is spilled into a puddle on the floor. If the density of gasoline is 0.665 g/mL, what volume in mL of gaso

Oksana_A [137]

Answer: 680ml

Explanation: (450grams)*(0.665g/ml) = 677 ml

6 0

2 years ago

What volume of 0.305 m agno3 is required to react exactly with 155.0 ml of 0.274 m na2so4 solution? hint: you will want to write

LuckyWell [14K]

The balanced chemical equation for reaction of $AgNO_{3}$ and $Na_{2}SO_{4}$ is as follows:

$2 AgNO_{3}+Na_{2}SO_{4}\rightarrow 2NaNO_{3}+Ag_{2}SO_{4}$

From the balanced chemical equation, 2 mol of $AgNO_{3}$ reacts with 1 mol of $NaNO_{3}$ .

First calculating number of moles of $NaNO_{3}$ as follows:

$M=\frac{n}{V}$

On rearranging,

$n=M\times V$

Here, M is molarity and V is volume. The molarity of $NaNO_{3}$ is given 0.274 M or mol/L and volume 155 mL, putting the values,

$n=0.274 mol/L\times 155\times 10^{-3}mL=0.04247 mol$

Since, 1 mol of $NaNO_{3}$ reacts with 2 mol of $AgNO_{3}$ thus, number of moles of $AgNO_{3}$ will be $2\times 0.04247 mol=0.08494 mol$ .

Now, molarity of $AgNO_{3}$ is given 0.305 M or mol/L thus, volume can be calculated as follows:

$V=\frac{n}{M}=\frac{0.08494 mol}{0.305 mol/L}=0.2785 L=278.5 mL$

Therefore, volume of $AgNO_{3}$ is 278.5 mL.

4 0

3 years ago

If a solution is saturated, which of these is true?

VARVARA [1.3K]

<span>The Answer would be </span><span>A)The concentration cannot be increased.</span><span> </span>

4 0

3 years ago

Read 2 more answers

A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di

Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

<em>Initial mass MnO₂ = 0.6467g</em>

<em>Recovered mass = 0.3104g</em>

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

<em>Moles MnO₂ -Molar mass: 86.9368g/mol-:</em>

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

<em>Moles Cl⁻:</em>

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

<em>Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:</em>

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

<em>0.3439g of AlCl₃</em> are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0

2 years ago