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3 years ago

PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS

Chemistry

1 answer:

julsineya [31]3 years ago

8 0

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

$Density \ of \ an \ object, \rho = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }$

$\rho = \dfrac{m}{V}$

Therefore, we have;

$The \ Density \ of \ the \ sodium \ carbonate, \ \rho = 0.4 \ g/dm^3 = \dfrac{m }{ 0.01 \ dm^3 }$

The mass, "m", of the sodium carbonate in = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

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Explanation:

The given data is as follows.

Mass of ice dropped = 325 g

Initial temperature = $30^{o}C$ = (30 + 273) K = 303 K

Final temperature = $0.0^{o}C$ = (0 + 273) K = 273 K

Now, using density of water calculate the mass of ice as follows.

$m_{ice} = \frac{500 ml \times 1.0 g/mol}{1 ml}$

= 500 g

As the relation between heat energy, specific heat and change in temperature is as follows.

Q = $m \times C_{p} \times dT$

= $\frac{500 g}{18 g/mol} \times 75.3 J/K/mol \times (303 - 273)K$

= 62750 J

Also, relation between heat energy and latent heat of fusion is as follows.

Q = m L

= $\frac{325 g}{18 g/mol} \times 6 \times 10^{3}$

= 108300 J

Therefore, we require $\frac{325 g}{18 g/mol} J$ heat but we have 40774.95 J.

So, $mass_{ice} = \frac{m \times C_{p} \times (T_{f} - T_{i})}{\Delta H_{f}}$

= $\frac{62750 J}{333}$

= 188.4 g

Hence, the mass of ice = 325 g - 188.4 g

= 137 g

Therefore, we can conclude that 137 g of ice will still be present when the contents of the pitcher reach a final temperature.

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3 years ago

Which equation represents a conservation of atoms? Group of answer choices LaTeX: 4Fe\:+3O_2\:\longrightarrow\:2Fe_2O_3 4 F e +

slamgirl [31]

Answer : The equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

Explanation :

Law of conservation of matter : It states that matter can neither be created nor be destroyed but it can only be transformed from one form to another form.

The balanced chemical reaction always follow the law of conservation of matter.

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

(1) The given chemical reaction is,

$4Fe+3O_2\rightarrow 2Fe_2O_3$

This reaction is a balanced chemical reaction in which number of atoms of iron and oxygen are equal on the both side of the reaction. So, this reaction obey the law of conservation of matter.

(2) The given chemical reaction is,

$2Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of iron and oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

(3) The given chemical reaction is,

$4Fe+2O_2\rightarrow 2Fe_2O_3$

This reaction is an unbalanced chemical reaction in which number of atoms of oxygen are not equal on the both side of the reaction. So, this reaction does not obey the law of conservation of matter.

Hence, the equation represents a conservation of atoms is:

$4Fe+3O_2\rightarrow 2Fe_2O_3$

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3 years ago

A student writes the following explanation of how certain molecules are formed.A process is used to chemically link smaller unit

tensa zangetsu [6.8K]

Answer:

polymerization

Explanation:

Student is explaining the process of formation of a polymer and the process is called polymerization.

Polymer is made up of joining repeating units. The repeating units are called monomers.

Properties of the polymer is determined by the structure of monomer molecule.

For example, consider a well-known polymer Teflon.is made by the polymerization of tetrafluoroethane.

Thus, the student is explaining polymerization.

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3 years ago

Meta-bromoaniline was treated with nano2 and hcl to yield a diazonium salt. Draw the product obtained when that diazonium salt i

Y_Kistochka [10]

Answer:

I believe is the correct answer

Explanation:

100bromoaniline+nano2+hcl

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2 years ago

A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea

Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume = 87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

4 0

2 years ago