Question

PLEASE HELP- I WILL GIVE BRAINLIEST AND THANKS

Answer 1

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

$Density \ of \ an \ object, \rho = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }$

$\rho = \dfrac{m}{V}$

Therefore, we have;

$The \ Density \ of \ the \ sodium \ carbonate, \ \rho = 0.4 \ g/dm^3 = \dfrac{m }{ 0.01 \ dm^3 }$

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.