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4 years ago

What is the substance called that is being dissolved in a solution?

Chemistry

2 answers:

Katena32 [7]4 years ago

6 0

Answer:

Solvent

Explanation:

The solvent is the substance that is being dissolved the other substance

Anna [14]4 years ago

5 0

Answer:

Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance. In the example above, the water is the solvent.

Explanation:

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A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

What makes an element inert?

ozzi

"The inert gases are obtained by fractional distillation of air, with the exception of helium which is separated from a few natural gas sources rich in this element, through cryogenic distillation or membrane separation. For specialized applications, purified inert gas shall be produced by specialized generators on-site. They are often used by chemical tankers and product carriers (smaller not a big as well as the tendency of inert gases vesselshtop specialized generators are also available for laboratories."

3 0

3 years ago

Lithium salts are often much less soluble in water than the corresponding salts of other alkali metals. For example, at 18°C, th

serious [3.7K]

Lithium is one of element of group 1 of periodic table.

Lithium has the smallest radius than as compared to the other elements, thus the density of the alkali metal is also less.

Lithium when added to water it floats, because of lower density. It eventually fizzes and becomes smaller.

The reaction on lithium and water is:

2Li + 2H₂O --> 2LiOH + H₂ (g)

The hydrogen gas which is liberated is highly flammable.

Thus, lithium salts are insoluble in water.

Density is defined as the mass of a substance per unit volume.

Density = Mass ÷ Volume.

To know more about Alkali metals, refer to this link:

brainly.com/question/5063184

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8 0

2 years ago

Calculate the initial molarity of MCHM in the river, assuming that the first part of the river is 7.60 feet deep, 100.0 yards wi

Effectus [21]

Answer:

[MCHM] = 7.52 M

Explanation:

This all about unit conversion

1 feet = 0.3048 meters

1 yard = 0.9144 meters

7.60 feet . 0.3048 = 2.31 meters deep

100 yd . 0.9144 meters = 91.44 meters long and 91.44 meters wide

In the river we have a volume of:

2.31 m . 91.44m . 91.44m = 19314.5 m³

1 dm³ = 1 L

1 dm³ = 0.001 m³

19314.5 m³ / 0.001 m³ = 19314542 L (The final volume of the river)

3.785 L = 1 gallon

In 19314542 L, we have (19314542 / 3.785) = 5102917 gallons

1 gallon = 128 oz

5102917 gallons . 128 = 653173376 oz

1 oz = 28.3495 g

653173376 oz . 28.495 = 1.86x10¹⁰ grams

Molar mass MCHM = 128 g/m

Moles of MCHM = 1.86x10¹⁰ grams / 128 g/m = 145312500 moles

Molarity = mol /L → 145312500 moles / 19314542 L = 7.52 M

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4 years ago

Which of these is a primary characteristic used to describe a clastic sedimentary rock?

FinnZ [79.3K]

The answer is B because to classify a sedimentary rock, it’s based on whatever minerals that are present

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2 years ago