Answer:
Chemical change
Explanation:
The rusting of iron/a nail is a chemical change
Iron (Fe) and Oxygen (O) combine to create the compound Iron Oxide (Fe2O3), which is rust.
Answer:
ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻
Explanation:
Sodium hypochlorite is a strong electrolyte that ionizes in sodium cation and hypochlorite anion.
NaClO(aq) ⇒ Na⁺(aq) + ClO⁻(aq)
ClO⁻ is a base that reacts with acetic acid (HC₂H₃O₂) from vinegar (neutralization reaction).
ClO⁻ + HC₂H₃O₂ ⇄ HClO + C₂H₃O₂⁻
Answer:
hope this will help you......
If you have an aqueous solution that contains 1.5 moles of HCl, the number of moles of ions in the solution is 3.0 moles.
<h2>Further Explanation
</h2><h3>Strong acids </h3>
- Strong acids are types of acids that undergo complete dissociation to form ions when dissolved in water.
- Examples of such acids are, HCl, H2SO4 and HNO3
- Dissociation of HCl
HCl + H₂O ⇔ H₃O⁺ + OH⁻
<h3>Weak acids </h3>
- Weak acids are types of acids that undergo incomplete dissociation to form ions when dissolved in water.
- Examples of such acids are acetic acids and formic acids.
- Dissociation of acetic acid
H₃COOH ⇔ CH₃COO⁻ + H⁺; CH₃COO⁻ is a conjugate base of acetic acid.
<h3>In this case;</h3>
- HCl which is a strong acid that ionizes completely according to the equation;
HCl + H₂O ⇔ H₃O⁺ + OH⁻
- From the equation, 1 mole of HCl produces 1 mole of H₃O⁺ ions and 1 mole of OH⁻ ions.
Therefore;
1.5 moles of HCl will produce;
= 1.5 moles of H₃O⁺ ions and 1.5 moles of OH⁻ ions.
This gives a total number ions of;
= 1.5 + 1.5
= 3 moles of ions
Keywords: Strong acid, weak acid, ions, ionization
<h3>Learn more about: </h3>
Level: High school
Subject: Chemistry
Topic: Salts, Acids and Bases
Answer:
The coefficient of thermal expansion α is
The coefficient of compressibility
Now considering 
From equation (1) we have that
From ideal equation
So
=> 
=> 
Explanation:
From the question we are told that
The coefficient of thermal expansion is 
The coefficient of compressibility is 
Generally the ideal gas is mathematically represented as
=> 
differentiating both side with respect to T at constant P
substituting the equation above into 
Recall from ideal gas equation 
So
Now differentiate equation (1) above with respect to P at constant T
substituting the above equation into equation of 
Recall from ideal gas equation that
So
Now considering
From equation (1) we have that
From ideal equation
So
=>
=>
