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ivanzaharov [21]
3 years ago
13

(A) The figure shows the setup which is used to observe an image formed wen a lighted candle is kept in front of a bi convex len

se.
1. Can the image be formed on the screen or not when the lighted candle is moved from F (focus) towards P (pole)?

2. Sketch the ray diagram to show how the image is formed by the lens when the candle is kept in between F and P.

3. Write 2 characteristics of the image formed in the above ray diagram.​
Physics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

<h3>1. In the case of candle flame , the object is placed beyond c , that means the image is formed or focused between c and f .in second case the object or sun is at infinity , so the image will be </h3><h3>formed at focus.this means the distance between image and lens has decreased in the second </h3><h3>case. either we have to move the screen towards the lens or the lens towards the screen.</h3>

Explanation:

I have posted the drawing.

in the second image

it is project c and characteristics

hope it helps u :)

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How much heat is removed from 60 grams of steam at 100 °C to change it to 60 grams
Harrizon [31]

Answer:

45200J

Explanation:

Given parameters:

Heat of vaporization of water  = 2260J/g

Mass of steam = 20g

Temperature = 100°C

Unknown:

Energy released during the condensation  = ?

Solution:

This change is a phase change and there is no change in temperature

To find the amount of heat released;

         H  = mL

m is the mass

L is the latent heat of vaporization

Insert the parameters and solve;

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4 0
2 years ago
Where would a Christmas tree be most likely to grow?
sveticcg [70]
Taiga is the answer.

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3 years ago
The ammonia molecule (NH3) has a dipole moment of 5.0×10?30C?m. Ammonia molecules in the gas phase are placed in a uniform elect
Neko [114]

Question (continuation)

(a) What is the change in electric potential energy when the dipole moment of a molecule changes its orientation with respect to E S from parallel to perpendicular?

(b) At what absolute temperature T is the average translational kinetic energy 3/2kT of a molecule equal to the change in potential energy calculated in part (a)?

Answer:

a. 9.0 * 10^-24 Joules

b. 0.44K

Explanation:

Given

Let p = dipole moment = 5.0 * 10^-30 Cm

Let E = Magnitude = 1.8 * 10^6 N/m

a.

The charge in electric potential = Final Charge - Initial Charge

Initial Charge = Potential Energy

Initial Energy = -pE cosФ where Ф = 0

So, initial Energy = - 5.0 * 10^-30 * 1.8 * 10^6

Initial Energy = -9 * 10^-24 Joules

Final Energy = 0

Charge = 0 - (-9.0 * 10^-24)

Charge = 9.0 * 10^-24 Joules

b.

Absolute Temperature

Change in Kinetic Energy = Change in Potential Energy = 9.0 * 10^-24

Change in Kinetic Energy = 3/2kT where k is Steven-Boltzmann constant = 1.38 * 10^-23

So,

9.0 * 10^-24 = 3/2 * 1.38 * 10^-23 * T

T = (9.0 * 10^-24 * 2)/(3 * 1.38 * 10^-23)

T = (18 * 10^-24)/(4.14 * 10^-23)

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6 0
3 years ago
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qaws [65]

Answer:

Pressure increases due to enlargement

Explanation:

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Pressure is same at the bottom of the cups (same level-Pascal's law)

thus, Air pressure 1 + h1d1g = Air pressure 2 + h2d1g

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from first and third, we get that AP1>AP3

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P+0.5dv^2 + gh is constant (also called the bernoulli equation

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for same flow rate, inc in area decreases the speed at which the blood flows as vA must remain same

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5 0
3 years ago
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Under specific circumstances, waves will bend around obstacles. This type of bending is called
BartSMP [9]
That type of bending is called "diffraction" of waves.
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