If you are talking about a 0.523 molar KI solution. You have to find the volume of the solution which can usually be assumed to just be that of water which would be 2 L in this case since 1mL=1g of water. Then you multiply 0.523M by 2L to get 1.046 moles of KI. After you get the number of moles you multiply that by its molar mass to get the grams.
(1.046 moles KI)x(165 grams/mole KI)= 172.59g KI
If you are talking about a 0.523 molal KI solution you have to multiply 0.523 molal by 2Kg to get 1.046 moles of KI. like before you have to multiply that by its molar mass to get grams.
The units for molarity is moles/L and the units of molality is moles(solute)/Kg(solvent)
Even though in this question the molarity and molatity appear to be the same thing, they are really not. Do not get the two confused with each other because if you have not seen already, they are different ways of measuring concentration and have their own uses.
Answer:
Explanation:
f the mass of an object is 35 grams and it takes up 7 cm3 of space, calculate the density.
34 pages
Answer:
D). Much lower than
Explanation:
When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is <u>Much lower than</u> the concentration of the ketone
because :
Carbon- oxygen bond is more stable(stronger) than Carbon-Carbon Bond
Keto - enol tautomerism is :
Ketone has C=O and enol has C=C
C=O bond energy is 745 kJ/mol
C=C bond energy is 614 kJ/mol
Answer:
d
Explanation:
soil need nutrient for it to help plant grow
Answer: The E for Silver-silver Chloride electrode = 0.287 V
Explanation:
Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.
Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V
