Answer:
c=0.14J/gC
Explanation:
A.
2) The specific heat will be the same because it is a property of the substance and does not depend on the medium.
B.
We can use the expression for heat transmission
In this case the heat given by the metal (which is at a higher temperature) is equal to that gained by the water, that is to say
for water we have to
c = 4.18J / g ° C
replacing we have
I hope this is useful for you
A.
2) El calor específico será igual porque es una propiedad de la sustancia y no depende del medio.
B.
Podemos usar la expresión para la transmisión de calor
En este caso el calor cedido por el metal (que está a mayor temperatura) es igual al ganado por el agua, es decir
para el agua tenemos que
c=4.18J/g°C
reemplazando tenemos
Answer:
Air flows from a high-pressure area to a low-pressure area.
Explanation:
<span>So this question based on doppler effect
Here apparent freq = freq of sound *(speed of sound-speed of observer)/(speed of sound-speed of source)
given
freq of sound=2000
speed of observer= 20
speed of source= 30
taking speed of sound as 343 m/s
apparent freq = 2000 [343 - 20] / [343 - 30] = 2063.90 Hz</span>
Multiply field strength (N/kg) by mass (kg) to get weight (N)
At the start, the car is carrying
4.7 kg * (9.8 N/kg) = 46.06 N
of fuel.
At the end, it is carrying
3.0 kg * (9.8 N/kg) = 29.4 N.
Assuming the car remains completely intact, its weight was reduced by
46.06 N - 29.4 N = 16.66 N.
Answer:
To drive at high speed around an unbanked horizontal curve on the earth.
Explanation:
Garvitational pull on on eart is 6 times more than on the moon. On. Earth, the vehicle will have more grip on the surface due to its weight. This grip will reduce its tendency to skid off the horizontal curve when compared to driving in the same unbanked horizontal curve on the moon.