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3 years ago

Which step is not part of a normal convection cycle?

Physics

2 answers:

meriva3 years ago

7 0

Answer:

B. Warmed air rises away from the surface.

Explanation:

It can be said that the convection cycle responsible for the dynamics of the lithospheric plates occurs not only in the nucleus, but also in the mantle and is transferred as a result transfers determined on the Earth's surface.

In this sense, we know that when the presence of a hot fluid occurs, the substances swell, which results in a reduction in density and then, this increases, since it is less dense than the medium where it is inserted. Thus, convection currents result from the heat flow that causes the hotter material, therefore less dense, to be propelled to the surface.

In summary, we can say that the normal convection cycle occurs when a hot fluid expands, it reduces density and rises because it is less dense than the surrounding environment. Convection currents are the result of the heat flow that makes the hotter material less dense and ascends the surface. This phenomenon occurs in the nucleus and in the mantle, and as a result it transfers certain heat from the interior to the Earth's surface.

Varvara68 [4.7K]3 years ago

4 0

Answer:

Air flows from a high-pressure area to a low-pressure area.

Explanation:

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garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

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3 years ago

A horizontal spring with spring constant 210 Nm is compressed by 20 cm and then used to launch a 250 g box across the floor. The

Damm [24]

Answer:

ugmd = 1/2 kx²

d = (1/2 kx²) / (ugm)

= (1/2 * 250 N/m * (0.2 m)²) / (0.23 * 9.81 m/s² * 0.3 kg)

= 7.4 m

ugmd = 1/2 mv²

v = √2ugd

= √(2(0.23)(9.81 m/s²)(7.4 m)

= 5.8 m/s

Explanation:

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3 years ago

Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most like

Assoli18 [71]

Reducing the amount of loops will cause a loss of strength, as the loops make the magnet stronger.

5 0

4 years ago

Read 2 more answers

Why are all bodies in nature electrically neutral? short answer please

DENIUS [597]

Answer: because they have equal numbers of protons

Explanation: Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion

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2 years ago

1. A 2.5 kg led projector is launched as a projectile off a tall building. At one point, as it

spin [16.1K]

Answer:

Explanation:

I got everything but i. Don't know why but it's eluding me. So let's do everything but that.

a. PE = mgh so

PE = (2.5)(98)(14) and

PE = 340 J

b. $KE=\frac{1}{2}mv^2$ so

$KE=\frac{1}{2}(2.5)(14)^2$ and

KE = 250 J

c. TE = KE + PE so

TE = 340 + 250 and

TE = 590 J

d. PE at 8.7 m:

PE = (2.5)(9.8)(8.7) and

PE = 210 J

e. The KE at the same height:

TE = KE + PE and

590 = KE + 210 so

KE = 380 J

f. The velocity at that height:

$380=\frac{1}{2}(2.5)v^2$ and

$v=\sqrt{\frac{2(380)}{2.5} }$ so

v = 17 m/s

g. The velocity at a height of 11.6 m (these get a bit more involed as we move forward!). First we need to find the PE at that height and then use it in the TE equation to solve for KE, then use the value for KE in the KE equation to solve for velocity:

590 = KE + PE and

PE = (2.5)(9.8)(11.6) so

PE = 280 then

590 = KE + 280 so

KE = 310 then

$310=\frac{1}{2}(2.5)v^2$ and

$v=\sqrt{\frac{2(310)}{2.5} }$ so

v = 16 m/s

h. This one is a one-dimensional problem not using the TE. This one uses parabolic motion equations. We know that the initial velocity of this object was 0 since it started from the launcher. That allows us to find the time at which the object was at a velocity of 26 m/s. Let's do that first:

$v=v_0+at$ and

26 = 0 + 9.8t and

26 = 9.8t so the time at 26 m/s is

t = 2.7 seconds. Now we use that in the equation for displacement:

Δx = $v_0t+\frac{1}{2}at^2$ and filling in the time the object was at 26 m/s:

Δx = 0t + $\frac{1}{2}(-9.8)2.7)^2$ so

Δx = 36 m

i. ??? In order to find the velocity at which the object hits the ground we would need to know the initial height so we could find the time it takes to hit the ground, and then from there, sub all that in to find final velocity. In my estimations, we have 2 unknowns and I can't seem to see my way around that connundrum.

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3 years ago