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3 years ago

Which step is not part of a normal convection cycle?

Physics

2 answers:

meriva3 years ago

7 0

Answer:

B. Warmed air rises away from the surface.

Explanation:

It can be said that the convection cycle responsible for the dynamics of the lithospheric plates occurs not only in the nucleus, but also in the mantle and is transferred as a result transfers determined on the Earth's surface.

In this sense, we know that when the presence of a hot fluid occurs, the substances swell, which results in a reduction in density and then, this increases, since it is less dense than the medium where it is inserted. Thus, convection currents result from the heat flow that causes the hotter material, therefore less dense, to be propelled to the surface.

In summary, we can say that the normal convection cycle occurs when a hot fluid expands, it reduces density and rises because it is less dense than the surrounding environment. Convection currents are the result of the heat flow that makes the hotter material less dense and ascends the surface. This phenomenon occurs in the nucleus and in the mantle, and as a result it transfers certain heat from the interior to the Earth's surface.

Varvara68 [4.7K]3 years ago

4 0

Answer:

Air flows from a high-pressure area to a low-pressure area.

Explanation:

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Energy is conventionally measured in Calories as well as in joules. One Calorie in nutrition is one kilocalorie, defined as 1 kc

IgorC [24]

Answer:

The answers to the questions are;

a. The number of times the student run the flight of stairs to lose 1.00 kg of fat is 829.23 times.

b. The average power output, in watts and horsepower, as he runs up the stairs is 158.026 watts.

c. The act of climbing the stairs is not a practical way to lose weight has to lose 1 kg of fat, the student needs to workout for about 26.49 hrs or 1.104 days.

Explanation:

To solve the question, we write out the known variables as follows

1 g of fat = 9.00kcal

Number of steps the student climbs = 95 steps

Height of each step = 0.150 m

Time it takes for the student to reach the top of the stairs = 57.5 s.

Efficiency of human muscles = 20 %

Mass of student, m = 65 kg

a. From the question, the energy expended by the student in climbing the stairs is the "work done" by the student.

The "work done" is the height climbed resulting in the gaining of gravitational potential energy P. E..

That is work done, W, = P. E. = m·g·h

Where:

h = The total height climbed by the student

g = Acceleration due to gravity = 9.81 m/s²

Therefore;

h = Height of each step × Number of steps the student climbs =

= 0.150 m/(step) × 95 steps = 14.25 m

Therefore, P. E. = 65 kg × 9.81 m/s² × 14.25 m = 9086.5125 kg·m²/s²

= 9086.5125 J

We remember that the efficiency of the muscle is 20 %

The formula for efficiency is

Efficiency = $\frac{Ene rgy Out put}{Energ y In put} \times 100 %$

The work produced by the muscle = Energy Output = 9086.5125 J

Energy input is given by

$\frac{Out put} {Effici ency}$ = 9086.5125 J/ (0.2) = 45432.5625 J

= 45.432 kJ

From the question, 1 g of fat = 9.00 kcal and

1 kcal = 4186 J

Therefore 1 g of fat can release 9.00 kcal × 4186 J = 37674 J

Therefore 1 kg of fat = 1000 g = 1000 × 37674 J = 37674 kJ

To consume the energy in 1 kg of fat the student therefore will run up the foight of stairs $\frac{37674 kJ}{45.432 kJ}$ times to make up the 37674 kJ energy contained in 1 kg of fat