Answer:
70.07 Hz
Explanation:
Since the sound is moving away from the observer then
and
when moving towards observer
With of 76 then taking speed in air as 343 m/s we have
Similarly, with of 65 we have
Now
v_s=27.76 m/s
Substituting the above into any of the first two equations then we obtain
This question involves the concepts of Newton's Second Law of Motion.
The acceleration of the bowling ball will be "0.67 m/s²".
<h3>Newton's Second Law of Motion</h3>According to Newton's Second Law of Motion, when an unbalanced force is applied on an object, it produces an acceleration in it, in the direction of the applied force. This acceleration is directly proportional to the force applied and inversely proportional to the mass of the object. Mathematically,
where,
Therefore,
a = 0.67 m/s²
Learn more about Newton's Second Law of Motion here:
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Answer:
2) 433 mph
Explanation:
The final velocity of the raindrop as it reaches the ground can be found by using the equation for a uniformly accelerated motion:
where
v is the final velocity
u = 0 is the initial velocity (the raindrop starts from rest)
a = g = 9.8 m/s^2 is the acceleration due to gravity
d = 2 km = 2000 m is the distance covered
Solving for v,
And keeping in mind that
1 mile = 1609 metres
1 hour = 3600 s
The speed converted into miles per hour is