Momentum = mass x velocity, so 500kg x 2m/s = 1000 kg m/s
A. Negatively charged
B. Positively charged
Answer:
right to vote, the right to a fair trial, the right to government services, the right to a public education, and the right to use public facilities.
Answer:
1287.5 N
Explanation:
We are given that
Mass of vehicle ,m=2100 kg
Weight of vehicle ,F=20,600 N
Area,A=
We have to find the minimum force that must be applied to the attached piston of area in order to lift the vehicle.
Apply the pascal's law
Answer:
The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
Explanation:
Given that,
Mass of the meter stick, m = 0.3 kg
Center of mass is located at its 45 cm mark.
We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :
or
So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.