3 years ago

5. A 500 N lady sits on the floor. How much force the floor exerts on her?

1 answer:

8 0

Explanation:

Force exerted by the floor on lady = Force exerted by the lady on the floor = Weight of the lady = 500N.

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Lilit [14]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wtjfavyw

8 0

3 years ago

Leokris [45]

Hey there!:

Molar mass MgCl2 = 95.2110 g/mol

So:

1 mole MgCl2 -------------- 95.2110 g

moles MgCl2 ---------------- 319 g

moles MgCl2 = 319 * 1 / 95.2110

moles MgCl2 = 319 / 95.2110

=> 3.350 moles of MgCl2

Hope that helps!

3 0

3 years ago

lora16 [44]

I think 43.12 I’m not that good with math

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4 years ago

sergeinik [125]

Answer:

Explanation:

7 mol AgCL * $\frac{1 mol AgNO3}{1 mol AgCl}$

You can cancel out the "mol AgCl" to get 7 moles of AgNO3

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2 years ago

Dmitry [639]

Is bubble chamber one of your choices? Bubble chamber sounds like a good fit for the question.

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3 years ago

5. A 500 N lady sits on the floor. How much force the floor exerts on her?​