Answer:
44 N
Explanation:
The electrostatic forces between two charges is given by:

where
k is the Coulomb's constant
q1 and q2 are the two charges
r is their separation
We notice that the force is directly proportional to the charges.
In this problem, initially we have a force of
F = 22 N
on a q2 = 4.0 C, exerted by a charge q1.
If the charge is doubled,
q2 = 8.0 C
This means that the force will also double, so it will be

A cart is pulled by horizontal force such that it moves with constant velocity
So here since velocity is constant we can say that its acceleration will be ZERO
now here for zero acceleration we can say

So here we will have

here we know that

so we will have


so here applied force on handle will be
<em>b. 10 N</em>
Answer:
Explanation:
any law stating that some quantity or property remains constant during and after an interaction or process, as conservation of charge or conservation of linear momentum.
D.) Travels in a pattern of particle motion....