Potassium is a crucial element for the healthy operation of the human

topjm [15]

Answer : 5.972 × 10^24 kg

3 0

3 years ago

A 2028 kg Oldsmobile traveling south on Abbott Road at 14.5 m/s is unable to stop on the ice covered intersection for a red ligh

Svetradugi [14.3K]

Answer:

v = 8.1 m/s

θ = -36.4º (36.4º South of East).

Explanation:

Assuming no external forces acting during the collision (due to the infinitesimal collision time) total momentum must be conserved.
Since momentum is a vector, if we project it along two axes perpendicular each other, like the N-S axis (y-axis, positive aiming to the north) and W-E axis (x-axis, positive aiming to the east), momentum must be conserved for these components also.
Since the collision is inelastic, we can write these two equations for the momentum conservation, for the x- and the y-axes:
We can go with the x-axis first:

$p_{ox} = p_{fx} (1)$

⇒ $m_{tr} * v_{tr}= (m_{olds} + m_{tr}) * v_{fx} (2)$

Replacing by the givens, we can find vfx as follows:

$v_{fx} = \frac{m_{tr}*v_{tr} }{(m_{tr} + m_{olds)} } = \frac{4146kg*9.7m/s}{2028kg+4146 kg} = 6.5 m/s (3)$

We can repeat the process for the y-axis:

$p_{oy} = p_{fy} (4)$

⇒ $m_{olds} * v_{olds}= (m_{olds} + m_{tr}) * v_{fy} (5)$

Replacing by the givens, we can find vfy as follows:

$v_{fy} = \frac{m_{olds}*v_{olds} }{(m_{tr} + m_{olds)} } = \frac{2028kg*(-14.5)m/s}{2028kg+4146 kg} = -4.8 m/s (6)$

The magnitude of the velocity vector of the wreckage immediately after the impact, can be found applying the Pythagorean Theorem to vfx and vfy, as follows:

$v_{f} = \sqrt{v_{fx} ^{2} +v_{fy} ^{2} }} = \sqrt{(6.5m/s)^{2} +(-4.8m/s)^{2}} = 8.1 m/s (7)$

In order to get the compass heading, we can apply the definition of tangent, as follows:

$\frac{v_{fy} }{v_{fx} } = tg \theta (8)$

⇒ tg θ = vfy/vfx = (-4.8m/s) / (6.5m/s) = -0.738 (9)

⇒ θ = tg⁻¹ (-0.738) = -36.4º

Since it's negative, it's counted clockwise from the positive x-axis, so this means that it's 36.4º South of East.

5 0

3 years ago

To protect their young in the nest, peregrine falcons will fly into birds of prey (such as ravens) at high speed. in one such ep

lozanna [386]

<span>The momentum of the falcon before collision is 0.6 * 20 = 12000 kgm/s which is actually the momenum of the falcon in the x-component. I had converted 600g to kg. After the collision the x-component of the raven is now mv2cos(thetha) where v2 is the final velocity of the raven and theta is the angle at which the falcon hits the raven. So we have that the falcon's final velocity = 600 * 5 * cos (theta). Likewise, after getting hit the the falcon, the raven's final momentum of is = m2v2cos(theta) = 1.5 * 9 * cos(theta). There's no motion along the y-components. So equating we have, momentum before collision = momentum after collision of the raven + momentum after collision of the falcon. So we have 12000 = 3000cos(theta) + 13.5cos(theta). Cos(theta)(3000 + 13.5) = 12000. Theta = cos^-1( 12000/3013.5 = 3.98 So theta =</span>

7 0

3 years ago

MULTIPLE CHOICE

Setler79 [48]

I'm pretty sure that the only right answer is <span>B) a north-seeking pole of unit strength with a south-seeking pole of the same strength. Because there are no single magnetic poles.</span>

3 0

3 years ago

Read 2 more answers

A person walking at 3.4 miles per hour change to mm/s

sp2606 [1]

3.4 miles/hour = 1519.936 mm/s

6 0

3 years ago