The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907
<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.</span>
Answer:
c. 44,950,000
Step-by-step explanation:
The following table is missing:
Year Attendance (millions)
1985 18.4
1990 25.2
1995 33.1
2000 37.6
Using a calculator, the line of best fit is obtained. Equation:
y = 1.31x - 2581.6
where y is attendance (in millions) and <em>x</em> is the year. Replacing with x = 2005 into the equation, we get:
y = 1.31(2005) - 2581.6
y = 44.95 millions or 44,950,000
Answer:
19x - 5y - 6
Hope this helped
Step-by-step explanation:
You start by simplifying each expression, you will be distributing the number outside the parentheses on each number inside the parentheses
1/2(30x+4y-14)
1/4(16x -28 +4)
leaving you with
15x + 2y - 7 + 4x - 7y + 1
combine the x's y's and the singular numbers
19x - 5y - 6
Brainliest?
I think 710 is the answer
266+266+89+89= 710
