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2 years ago

What is Dalton's law of partial pressure

Chemistry

2 answers:

guapka [62]2 years ago

8 0

Answer:

Dalton law of partial pressure states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of partial pressures of the individual gases.

Explanation:

Pt=P1+P2

Leto [7]2 years ago

7 0

If 3 substances be x,y,z

$\\ \tt\longmapsto P_{net}=P_x+P_y+P_z$

Where

$\\ \tt\longmapsto P_x=\dfrac{n_xRT}{V}$

$\\ \tt\longmapsto P_y=\dfrac{n_yRT}{V}$

$\\ \tt\longmapsto P_z=\dfrac{n_zRT}{V}$

P is partial pressure
n is number of moles
V is volume
T is temperature

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What is the total number of moles represented by 20 grams of CACO3

Nutka1998 [239]

Answer:

B. 0.2.

Explanation:

We can use the relation:

n = mass/molar mass

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How many molecules are in 7.62 L of CH4, at 87.5°C and 722 torr

pickupchik [31]

Answer: There are $1.469 \times 10^{23}$ molecules present in 7.62 L of $CH_4$ at $87.5^{o}C$ and 722 torr.

Explanation:

Given : Volume = 7.62 L

Temperature = $87.5^{o}C = (87.5 + 273) K = 360.5 K$

Pressure = 722 torr

1 torr = 0.00131579

Converting torr into atm as follows.

$722 torr = 722 torr \times \frac{0.00131579 atm}{1 torr}\\= 0.95 atm$

Therefore, using the ideal gas equation the number of moles are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

$PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol$

According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{23}$ atoms. Hence, number of atoms or molecules present in 0.244 mol are calculated as follows.

$0.244 mol \times 6.022 \times 10^{23}\\= 1.469 \times 10^{23}$

Thus, we can conclude that there are $1.469 \times 10^{23}$ molecules present in 7.62 L of $CH_4$ at $87.5^{o}C$ and 722 torr.

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