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2 years ago

7

What is Dalton's law of partial pressure

2 answers:

guapka [62]2 years ago

8 0

Answer:

Dalton law of partial pressure states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of partial pressures of the individual gases.

Explanation:

Pt=P1+P2

Leto [7]2 years ago

7 0

If 3 substances be x,y,z

$\\ \tt\longmapsto P_{net}=P_x+P_y+P_z$

Where

$\\ \tt\longmapsto P_x=\dfrac{n_xRT}{V}$

$\\ \tt\longmapsto P_y=\dfrac{n_yRT}{V}$

$\\ \tt\longmapsto P_z=\dfrac{n_zRT}{V}$

P is partial pressure
n is number of moles
V is volume
T is temperature

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Who uses holmium? I need to know for a science project.

Tanzania [10]

Answer:

Holmium can absorb neutrons, so it is used in nuclear reactors to keep a chain reaction under control. Its alloys are used in some magnets. Holmium has no known biological role, and is non-toxic. Holmium is found as a minor component of the minerals monazite and bastnaesite.

Explanation:

this is basically used in industries

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3 years ago

How do you know when a chemical equation is balanced?

kirza4 [7]

Both sides of the equation would be equal.

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6 0

3 years ago

Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin

Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

$\mathsf{In \dfrac{C}{C_o} = -kt}$

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

$\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}$

㏑(0.01369863014) = -(0.12) t

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3 0

3 years ago

A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica

Sladkaya [172]

Answer: The empirical formula for the given compound is $CH_5N$

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = $\frac{3.23}{3.23}=1$

For Hydrogen = $\frac{16.2}{3.23}=5.01\approx 5$

For Oxygen = $\frac{3.24}{3.23}=1.00\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is $C_1H_5N_1=CH_5N$

3 0

3 years ago

How many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?

Lostsunrise [7]

Answer:

0.012288122055459

Explanation:

i might be wrong

6 0

3 years ago