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SVETLANKA909090 [29]
4 years ago
6

The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnel

s. (a) Determine its fundamental frequency of vibration. (b) What harmonic must be excited so that it resonates in the audio region at 20 Hz or greater?
Physics
1 answer:
Marina CMI [18]4 years ago
3 0
For a cylinder that has both ends open resonant frequency is given by the following formula:
f= \frac{nv}{2L}
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
f_0= \frac{v}{2L}=\frac{343}{2\cdot 2779}=0.062 Hz
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
20= \frac{n343}{2\cdot 2779} =n\cdot f_0
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
20=n\cdot f_0\\ n=\frac{20}{0.062}=322.58
Since n has to be an integer, final answer would be 323.

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How old is a bone if it still has 50% of its carbon-14 content?
Degger [83]

Answer:

5730 years

Explanation:

The half life of carbon-14 is 5730 years.  If 50% of the carbon-14 remains, then exactly 1 half life has passed.

The half-life equation is:

A = A₀ (½)^(t / T)

where A is the remaining amount,

A₀ is the initial amount,

t is time,

and T is the half life.

In this case, A = ½ A₀ and T = 5730.

½ A₀ = A₀ (½)^(t / 5730)

½ = (½)^(t / 5730)

1 = t / 5730

t = 5730

6 0
3 years ago
To determine athletes body fat, there are weighed first in air and then again while they are completely underwater. It is found
rodikova [14]

Answer:

1065 Kgm-3

Explanation:

We can determine the relative density of the athlete from the formula;

Relative density of athlete = weight of athlete in air/upthrust on athlete

Since weight of athlete in air= 690 N

Weight of athlete in water = 42 N

Upthrust on athlete= weight in air - weight in water

Upthrust on athlete= 690 N - 42 N = 648 N

Relative density of athlete= 690 N / 648 N

Relative density of athlete= 1.065

Therefore, average density of the athlete= relative density × density of water = 1.065 × 1000 Kgm-3 = 1065 Kgm-3

4 0
4 years ago
A car has a speed of 2m/s and a mass of 1500 kg. what is the car's kinetic energy
larisa86 [58]
We have: K.E. = mv² / 2
Here, m = 1500 Kg
v = 2 m/s

Substitute their values in the formula, 
K.E. = 1500 ×2² / 2
K.E. = 6000 / 2
K.E. = 3000 J or 3 KJ

Finally, answer of your question would be 3000 Joule or 3 Kilojoule

Hope this helps!
4 0
3 years ago
Read 2 more answers
Light travels in what wave
Rina8888 [55]
Light travels<span> as a </span>wave<span>. But unlike sound </span>waves<span> or water </span>waves<span>, it does not need any matter or material to carry its energy along. This means that </span>light<span> can </span>travel<span> through a vacuum—a completely airless space.</span>
4 0
3 years ago
Read 2 more answers
A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary
Anuta_ua [19.1K]

Answer:

Explanation:

Conservation of momentum during the collision

0.023(230) + 2.0(0.0) = 0.023(170) + 2.0v

v = 0.69 m/s

The initial block kinetic energy will be converted to friction work

½mv² = Fd = μmgd

½(2.0)(0.69²) = 0.15(2.0)(9.8)d

d = 0.1619387... m

d = 16 cm

6 0
3 years ago
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