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elena-s [515]
3 years ago
9

Creek and Cold stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks an

other $30$ yards each. In yards, how far are Creek and Cold from one another?

Physics
1 answer:
Stella [2.4K]3 years ago
7 0

[See the attached picture for better Understanding]

Answer:

After walking 40 yards in opposite directions and then 30 yards to left, Creek and Cold are now standing at the edges of tow triangles and the distance between them is the hypotenuse of two triangles with same measurments. So by using pythagoras theorem we can state that,

Distance between both of them is 100 yards.

See the attached picture.

Explanation:

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6 0
3 years ago
A 1-kg block is lifted vertically 1 m at constant speed by a boy. The work done by the boy is about:
Igoryamba

Answer:

9.8\; {\rm J}, assuming that the gravitational field strength is g = 9.8\; {\rm N \cdot kg^{-1}}.

Explanation:

Notice that both the speed and the direction of motion of this block are constant. In other words, the velocity of this block is constant.

By Newton's Second Law, the net force on this block would be 0. External forces on this block should be balanced. Thus, the magnitude of the (downward) weight of this block should be equal to the magnitude of the (upward) force that the boy applies on this block.

Let m denote the mass of this block. It is given that m = 1\; {\rm kg}. The weight of this block would be:

\begin{aligned}\text{weight} &= m\, g \\ &= 1\; {\rm kg} \times 9.8\; {\rm N \cdot kg^{-1}} \\ &= 9.8\; {\rm N}\end{aligned}.

Hence, the force that the boy applies on this block would be upward with a magnitude of F = 9.8\; {\rm N}.

The mechanical work that a force did is equal to the product of:

  • the magnitude of the force, and
  • the displacement of the object in the direction of the force.

The displacement of this block (upward by s = 1\; {\rm m}) is in the same direction as the (upward) force that this boy had applied. Thus, the work that this boy had done would be the product of:

  • the magnitude of the force that this boy exerted, F = 9.8\; {\rm N}, and
  • the displacement of this block in the direction, s = 1\; {\rm m}.

\begin{aligned}\text{work} &= F\, s \\ &= 9.8\; {\rm N} \times 1\; {\rm m} \\ &= 9.8\; {\rm J}\end{aligned}.

5 0
2 years ago
A climber pulls herself 8 meters upwards with a force of 150 Newtons. If it takes her 16 seconds to cover the 8 meters, how much
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Answer:

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Explanation:

given,

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Time, t = 16 s

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W = 150 x 8

W = 1200 J

We know,

Power =\dfrac{Work\ done}{time}

P =\dfrac{1200}{16}

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Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is

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18 N + <em>F</em>₃ = -12 N

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So <em>F</em>₃ has a magnitude of 30 N and points west.

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3 years ago
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