-38.26dB is the intensity level of the sound for the more distant listener relative to that for the nearer listener
By using the <u>inverse square law,</u>
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As one listener is 81.9 times farther away from the source of the sound than the other.
Then Increasing the distance by 81.9 times reduces the intensity by
= 6707.61 times
The intensity level of the sound (in decibels) for the more distant listener relative to that for the nearer listener is:
= 10log(ratio of intensities)
= 10log(1/6707.61)
= 10log(0.000149)
=10 × -3.826
= -38.26dB (The negative sign represents the sound is less intense for the farther listener)
So, the intensity level of the sound (in decibels) for the more distant listener relative to that for the nearer listener is -38.26dB
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The amount of movement, linear momentum, momentum or momentum is a physical quantity derived from a vector type that describes the movement of a body in any mechanical theory. In classical mechanics, the amount of movement is defined as the product of body mass and its velocity at a given time.
p= mv
Where,
m = mass
v = Velocity
Our values are given as,
Replacing we have that,
Therefore the momentum is
Answer:
1 angstrom = 0.1nm
5000 angstrom = 5000/1 × 0.1nm
<h3>= 500nm</h3>5000 angstrom = 5000 × 1 × 10^-10
<h3>= 5 × 10^-7 m</h3>Hope this helps you
Answer:
Explanation:
The force on the point charge q exerted by the rod can be found by Coulomb's Law.
Unfortunately, Coulomb's Law is valid for points charges only, and the rod is not a point charge.
In this case, we have to choose an infinitesimal portion on the rod, which is basically a point, and calculate the force exerted by this point, then integrate this small force (dF) over the entire rod.
We will choose an infinitesimal portion from a distance 'x' from the origin, and the length of this portion will be denoted as 'dx'. The charge of this small portion will be 'dq'.
Applying Coulomb's Law:
The direction of the force on 'q' is to the right, since both charges are positive, and they repel each other.
Now, we have to write 'dq' in term of the known quantities.
Now, substitute this into 'dF':
Now we can integrate dF over the rod.