Answer:
(a) μ = 0.015kg/m
(b) v = 90.64m/s
Explanation:
(a) The linear density of the string is given by the following relation:
(1)
m: mass of the string = 25.3g = 25.3*10-3 kg
L: length of the string = 1.62m
The linear density of the string is 0.015kg/m
(b) The velocity of the string for the fundamental frequency is:
(2)
f1: fundamental frequency = 41.2 Hz
vs: speed of the wave
l: distance between the fixed extremes of the string = 1.10m
You solve for v in the equation (2) and replace the values of the other parameters:
The speed of the wave for the fundamental frequency is 90.64m/s
Answer:
A) 60%
B) p2 = 1237.2 kPa
v2 = 0.348 m^3
C) w1-2 = w3-4 = 1615.5 kJ
Q2-3 = 60 kJ
Explanation:
A) calculate thermal efficiency
Л = 1 -
where Tl = 300 k
Th = 750 k
hence thermal efficiency ( Л ) = [1 - ( 300 / 750 )] * 100 = 60%
B) calculate the pressure and volume at the beginning of the isothermal expansion
calculate pressure ( P2 ) :
= P3v3 = mRT3 ----- (1)
v3 = 0.4m , mR = 2* 0.287, T3 = 750
hence P3 = 1076.25
next equation to determine P2
Qex = p3v3 ln( p2/p3 )
60 = 1076.25 * 0.4 ln(p2/p3)
hence ; P2 = 1237.2 kpa
calculate volume ( V2 )
p2v2 = p3v3
v2 = p3v3 / p2
= (1076.25 * 0.4 ) / 1237.2
= 0.348 m^3
C) calculate the work and heat transfer for each four processes
work :
W1-2 = mCv( T2 - T1 )
= 2*0.718 ( 750 - 300 ) = 1615.5 kJ
W3-4 = 1615.5 kJ
heat transfer
Q2-3 = W2-3 = 60KJ
Q3-4 = 0
D ) sketch of the cycle on p-V coordinates
attached below
Answer:
0.4cm
Explanation:
First, you calculate the dis acceleration of the electron generated by the potential difference between the plates:
(1)
q: charge of the electron = 1.6*10^-19 C
V: potential difference between plates = 100V
m: mass of the electron
d: distance between parallel plates = 1cm = 0.01m
by replacing the values of the parameters you obtain:
you use this value in the following kinematic equation:
(2)
v: final velocity = 0m/s (until the electron stops)
from the equation (2) you calculate x, the distance traveled by the electron. But before you calculate the initial velocity of the electron by using the following equation:
Next, you replace vo in (2) to obtain x:
Then, the electron travels 0.1cm from the middle of the region between the parallel plates, hence, the distance between the electron and the negatve plate is:
0.5cm-0.1cm=0.4cm