Step-by-step explanation:
px^2-qx+r
p(x^2-q/px)+r
p[(x^2-q/px +(q/2p)^2_(q/2p)^2)]+r
p[(x-q/2p)^2 -q^2/4p^2)]+r
p(x-q/2p)^2 -q^/4p+r
p(x-q/2p)^2-(q^2-4pr)/4p
Solution :
a). The test is a left tailed test.
b). The sample proportion is :
= 0.065
Determining the Z statistics using the formula :
= -2.31
∴ Z statistics value is -2.31
c). Using the excel function, the P-value is :
P-value = Normsdist(-2.31)
= 0.0104441
d). The null hypothesis is
The level of significance is 0.01
We fail to reject the null hypothesis as the P value is less than or equal to the significant level.
It will take one person for the venues to equal the same amount. This is simply done by multiplying 1 x the per person amount then adding it to the reservation cost.
Answer:
B. 10 + 4x ≤ 200
Step-by-step explanation: