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4 years ago

Which of the following research questions would be the most appropriate selection for a student studying space exploration?

Chemistry

1 answer:

svetoff [14.1K]4 years ago

4 0

B. What potential resources could be gained from the rise of asteroid mining ?

You might be interested in

How many mm Hg are there in 2.27 atm?

vekshin1

Answer:

$\huge\boxed{\sf 2.27\ atm = 1,725\ mm\ of\ Hg}$

Explanation:

We know that:

1 atm = 760 mm of Hg (Standardly)

Multiply both sides by 2.27

2.27 atm = 760 * 2.27 mm of Hg

2.27 atm = 1,725 mm of Hg

$\rule[225]{225}{2}$

Hope this helped!

3 0

3 years ago

An acid has a molarity of 0.01 M. What does the 0.01 M refer to?

bulgar [2K]

Answer : The correct option is, The concentration of the acid.

Explanation :

Molarity : Molarity is defined as the moles of solute present in one liter of the solution. Or it is defined as the concentration of solute present in one liter of solution.

The unit of molarity is, (M) i.e, mole/liter. It is also known as molar concentration.

Molarity of 0.01 M means, 0.01 concentration of the acid present in the solution.

Therefore, the 0.01 M refer to the concentration of the acid.

5 0

4 years ago

Read 2 more answers

How many neutrons would Oxygen-19 have

Softa [21]

Oxygen has 7 neutrons

8 0

3 years ago

Read 2 more answers

If one atom of oxygen is neutral and another atom of oxygen is an ion do they have to differ in mass?

Gala2k [10]

Maybe lol, because if one is an in and another is a neutral, it makes two balls, then afterwards, you'll need a big stick!

3 0

4 years ago

The following reaction has Kp = 109 at 25°C. 2 NO(g) + Br2(g) equilibrium reaction arrow 2 NOBr(g) If the equilibrium partial pr

kati45 [8]

<u>Answer:</u> The equilibrium partial pressure of NO is 0.0034 atm

<u>Explanation:</u>

For the given chemical equation:

$NO(g)+Br_2(g)\rightleftharpoons 2NOBr(g)$

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{NOBr})^2}{p_{NO}\times p_{Br_2}}$

We are given:

Equilibrium partial pressure of $Br_2$ = 0.0159 atm

Equilibrium partial pressure of NOBr = 0.0768 atm

$K_p=109$

Putting values in above equation, we get:

$109=\frac{(0.0768)^2}{p_{NO}\times 0.0159}\\\\p_{NO}=0.0034atm$

Hence, the equilibrium partial pressure of NO is 0.0034 atm

3 0

3 years ago