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Alex Ar [27]
3 years ago
8

In the hydrogenation of ethylene using a nickel catalyst, the initial concentration of ethylene is 2.00mol?L?1 and its rate cons

tant (k) is0.0020mol?L?1?s?1 . Determine the rate of reaction if it follows a zero-order reaction mechanism.
Express your answer to two significant figures and include the appropriate units.
Chemistry
1 answer:
gavmur [86]3 years ago
8 0

Answer:

The rate of reaction of a zero-order reaction  is 0.0020 mol/L.

Explanation:

The rate expression of the zero order kinetic are :

R=k[A]^o

[A]= initial concentration of reactant

k = rate constant

R = rate of reaction

We have :

Rate constant of the reaction , k = 0.0020 mol/L s

R=0.0020 mol/L s\times 1

R = 0.0020 mol/L s

The rate of reaction of a zero-order reaction  is 0.0020 mol/L.

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LenKa [72]
Around 36 or 37 days, because of the decimal
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2 years ago
Addition of water to an alkyne gives a keto‑enol tautomer product. Draw an enol that is in equilibrium with the given ketone
Marrrta [24]

Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
  2. If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
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7 0
2 years ago
Find the volume of a gas if 3.6 mols of the gas is at STP
Digiron [165]

Answer:

81 L gas

General Formulas and Concepts:

<u>Ideal Gas Law</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.6 mols gas at STP

[Solve] volume (L) of gas

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.6 \ mol \ gas(\frac{22.4 \ L \ gas}{1 \ mol \ gas \ at \ STP})
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 80.64 \ L \ gas

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

80.64 L gas ≈ 81 L gas

6 0
3 years ago
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8 0
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3 years ago
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