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Alex_Xolod [135]
3 years ago
15

Will the decimal point be moving to the right or to the left? How do you know?

Physics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer: Example 2.39 move decimal to the right to get rid of the decimal same for .09 move the decimal to the left to get rid of it or if it ask how many to move to the left just move that many

Explanation:

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The song Arirang is an example of korean F_L_ _O N_​
sergij07 [2.7K]
Folk song

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7 0
2 years ago
1. What is the kinetic energy of a 1.75 kg ball travelling at a speed of 54 m/s?
Over [174]

Answer:

We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Explanation:

Given

  • Mass m = 1.75 kg
  • Velocity v = 54 m/s

To determine

Kinetic Energy (K.E) = ?

We know that a body can possess energy due to its movement — Kinetic Energy.

Kinetic Energy (K.E) can be determined using the formula

K.E=\frac{1}{2}mv^2

where

  • m is the mass (kg)
  • v is the velocity (m/s)
  • K.E is the Kinetic Energy (J)

now substituting m = 1.75, and v = 54 in the formula

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}\left(1.75\right)\left(54\right)^2

K.E=1458\times 1.75

K.E=2551.5 J

Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

7 0
3 years ago
Sound waves cannot carry energy through. A water B air C a mirror D a vacuum
Ber [7]
I looked up the question and got D- a vacuum
3 0
3 years ago
The plane of a rectangular coil, 7.2 cm by 3.7 cm, is perpendicular to the direction of a uniform magnetic field B. If the coil
netineya [11]

Answer:

The rate of change of magnetic field is 2.23 T/s.              

Explanation:

Given that,

Dimension of rectangular coil is 7.2 cm by 3.7 cm.

Number of turns in the coil, N = 104

Resistance of the coil, R = 12.4 ohms

Current, I = 0.05 A

We need to find the rate of change of magnetic field in the coil. The induced emf is given by the rate of change of magnetic flux. So,

\epsilon=-\dfrac{d\phi}{dt}

Ohm's law is :

\epsilon=IR

So,

IR=-\dfrac{d\phi}{dt}\\\\IR=-\dfrac{d(NBA)}{dt}\\\\IR=-NA\dfrac{dB}{dt}\\\\\dfrac{dB}{dt}=\dfrac{IR}{NA}\\\\\dfrac{dB}{dt}=\dfrac{0.05\times 12.4}{104\times 7.2\times 10^{-2}\times 3.7\times 10^{-2}}\\\\\dfrac{dB}{dt}=2.23\ T/s

So, the rate of change of magnetic field is 2.23 T/s.

4 0
3 years ago
How far will 20 N of force stretch a spring with a spring constant of 140 N/m?
densk [106]

Answer:

0.143 m

Explanation:

The relationship between force applied on a string and stretching of the spring is given by Hooke's law:

F=kx

where

F is the force exerted on the spring

k is the spring constant of the spring

x is the stretching of the spring from its equilibrium position

In this problem, we have:

F = 20 N is the force applied on the spring

k = 140 N/m is the spring constant

Solving for x, we find how far the spring will stretch:

x=\frac{F}{k}=\frac{20}{140}=0.143 m

7 0
3 years ago
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