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Katena32 [7]
3 years ago
5

A 1.5 kg tether ball is hit so that it circles the pole with an angular speed of 4m/s

Physics
1 answer:
My name is Ann [436]3 years ago
5 0

Well, you didn't ask a question, and 4 m/s is not an angular speed.
So all I can offer is a couple of observations:

1). The tension in the rope is

      M V² / R  =  (1.5 kg) x (4 m/s)² / R

                     =  (24 kg-m²/s²) / (distance of the ball from the pole).

2).  Tetherball was the only thing I played at camp,
       more than 60 years ago, and I loved it !
       It was a tough game, because we had to skin
       our own T.Rex and use his hide to make the ball
       and his guts for the rope. 
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3 years ago
Lloyd is standing on a scaffolding 12 meters above the ground to clean the windows of a tall building. His bucket, which has a m
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Answer:

U₂ = 20 J

KE₂ = 40 J

v= 12.64 m/s

Explanation:  

Given that

H= 12 m

m = 0.5 kg

h= 4 m

The potential energy at position 1

U₁ = m g H

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The potential energy at position 2

U₂ = m g h

U ₂= 0.5 x 10 x 4        ( take g= 10 m/s²)

U₂ = 20 J

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The kinetic energy at position 2

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From energy conservation

U₁+KE₁=U₂+KE₂

By putting the values

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3 0
3 years ago
Read 2 more answers
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