Ah ha ! Very interesting question.
Thought-provoking, even.
You have something that weighs 1 Newton, and you want to know
the situation in which the object would have the greatest mass.
Weight = (mass) x (local gravity)
Mass = (weight) / (local gravity)
Mass = (1 Newton) / (local gravity)
"Local gravity" is the denominator of the fraction, so the fraction
has its greatest value when 'local gravity' is smallest. This is the
clue that gives it away.
If somebody offers you 1 chunk of gold that weighs 1 Newton,
you say to him:
"Fine ! Great ! Golly gee, that's sure generous of you.
But before you start weighing the chunk to give me, I want you
to take your gold and your scale to Pluto, and weigh my chunk
there. And if you don't mind, be quick about it."
The local acceleration of gravity on Pluto is 0.62 m/s² ,
but on Earth, it's 9.81 m/s.
So if he weighs 1 Newton of gold for you on Pluto, its mass will be
1.613 kilograms, and it'll weigh 15.82 Newtons here on Earth.
That's almost 3.6 pounds of gold, worth over $57,000 !
It would be even better if you could convince him to weigh it on
Halley's Comet, or on any asteroid. Wherever he's willing to go
that has the smallest gravity. That's the place where the largest
mass weighs 1 Newton.
Answer:
False
Explanation:
This proposition is false because by example the sun exerts a force over the earth and them are not in contact
Answer:
Height will be 3.8971 m
Explanation:
We have given that radius of the solid r = 1.60 m
Mass of the solid disk m = 2.30 kg
Angular velocity 
Moment of inertia is given by 
Transnational Kinetic energy is given by
as we know that v = 
So 
Rotational kinetic energy is given by 
Potential energy is given by mgh
According to energy conservation


When four atomic orbitals are mixed to form hybrid orbitals, 4 x sp3
hybrid orbitals are formed.
<span>Carbon's 2s and all three of its 3p </span>orbitals<span> hybridize to form four sp</span>3 orbitals. These orbitals<span> then bond with four hydrogen atoms through sp</span>3-s <span>orbital </span>overlap, creating methane.