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diamong [38]
3 years ago
7

An electric motor transforms potential energy into mechanical energy.True or false ​

Physics
2 answers:
Westkost [7]3 years ago
8 0

Answer: true

Explanation:

Citrus2011 [14]3 years ago
8 0
True bc it is becoming energy
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If pressurized air pressure is 350 kPa, atmospheric pressure is 100 kPa, initial atmospheric pressure is 100 kPa, initial accele
Travka [436]

Answer:

d=8.657mm

Explanation:

From the question we are told that

Pressurized air pressure is P_{air}=350 kPa,

Atmospheric pressure is P_a=100 kPa

Initial acceleration of the water rocket is a_i=0.5g.

Acceleration of the water rocket is  a_r=0.5g

Mass of water is M_w=0.5 kg

Generally total mass is given mathematically given as

T_M=0.5+0.5=>1kg

Generally the tension on the rocket is given mathematically given as

T=(P_{air}-P_a)A

T=(350-100) \frac{\pi d^2}{4}

T is also

T=\frac{3Mg}{2}

Therefore

T=>(350-100) \frac{\pi d^2}{4}= \frac{3Mg}{2}

T=>(350-100) \frac{\pi d^2}{4}= \frac{3*1*9.81}{2}

d^2= \frac{3*1*9.81*4}{2(350-100) \pi}

d=\sqrt{\frac{3*1*9.81*4}{2(350-100) \pi}}

d=8.657mm

therefore diameter of nozzle is mathematically given as

d=8.657mm

8 0
3 years ago
No wait... That's still not right... The cart was at the point x = 2.8 when t = 0.0 s, but it already had an initial velocity of
polet [3.4K]

Solution :

Velocity of cart at t = 0 s is, u = 1.8 m/s .

Distance covered in 3 seconds is :

d = 1.8 m/s × 3 s

d = 5.4 m.

So, position of cart after t = 3 seconds is x = 2.8 + 5.4 m = 8.2 m .

Hence, this is the required solution.

8 0
3 years ago
1. How does RNA differ from DNA?
9966 [12]
The answer is c) RNA contains uracil and ribose.
7 0
3 years ago
Read 2 more answers
What are 3d glasses made of?
masha68 [24]
<span>a) two filters with vertical polarization
</span>
8 0
4 years ago
Read 2 more answers
A wire carries 3.7 A of current. A second wire is placed parallel to the first 8.0 cm away. What is the current flowing through
IgorC [24]

Answer:

The current in second wire is 5.0 A.

(B) is correct option.

Explanation:

Given that,

Current in first wire = 3.7 A

Distance = 8.0 cm

We need to calculate the magnetic field due to the current carrying wire

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

Where, I = current

r = distance

Put the value into the formula

For first wire

B = \dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}...(I)

For second wire,

The distance is 8-3.7 =  4.3 cm

B' = \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}...(II)

The magnetic field in both the wires,

From equation (I) and (II)

\dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}= \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}

I'=\dfrac{3.7\times4.3\times10^{-2}}{3.4\times10^{-2}}

I'=4.68\ A\ approx = 5.0\ A

Hence, The current in second wire is 5.0 A.

8 0
4 years ago
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