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diamong [38]
3 years ago
7

An electric motor transforms potential energy into mechanical energy.True or false ​

Physics
2 answers:
Westkost [7]3 years ago
8 0

Answer: true

Explanation:

Citrus2011 [14]3 years ago
8 0
True bc it is becoming energy
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There are Z protons in the nucleus of an atom, where Z is the atomic number of the element. An α particle carries a charge of +2
qaws [65]

Answer:

r = 2.84 \times 10^{-14} m

Explanation:

As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle

So here we can write it as

\frac{1}{2}mv^2 = \frac{k(2e)(ze)}{r}

now we know that

m = 1.67 \times 10^{-27} kg

e = 1.6 \times 10^{-19} C

z = 79

here kinetic energy of the incident alpha particle is given as

KE = 6.4 \times 10^{-13} J

now we have

6.4 \times 10^{-13} = \frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r}

now we have

r = 2.84 \times 10^{-14} m

7 0
3 years ago
Can You Please Give Me Some Examples of Density-Independent and Density-Dependent Limiting Factors?
ivolga24 [154]
Density-Dependent: 
1<span><span><span><span>. </span>competition.</span><span>   
<span>2. </span>overcrowding.</span><span>   
3<span>. </span>predators.</span></span><span> 

(These are a few from a test I took, hopefully they help you a bit >.<)</span></span>
7 0
3 years ago
During a new moon, the moon is between the
mylen [45]
The moon is between the sun and earth.


The side where the light from the sun hits the moon is facing away from earth.
5 0
3 years ago
If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he
forsale [732]
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q= mC_s \Delta T
where m is the mass of the substance, Cs is its specific heat capacity and \Delta T is the increase of temperature.

If we re-arrange the formula, we get
C_s =  \frac{Q}{m \Delta T}
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
C_s =  \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C
6 0
3 years ago
Read 2 more answers
A 235 kg crate is pulled across a horizontal surface with a force of 760 N applied at an
AnnyKZ [126]

Answer:

658.16N

Explanation:

Step one:

given data

mass m= 235kg

Force F= 760N

angle= 30 degrees

Required

The horizontal component of the force

Step two:

The horizontal component of the force

Fh= 760cos∅

Fh=760cos30

Fh=760*0.8660

Fh=658.16N

3 0
3 years ago
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