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3 years ago

An electric motor transforms potential energy into mechanical energy.True or false

Physics

2 answers:

Westkost [7]3 years ago

8 0

Answer: true

Explanation:

Citrus2011 [14]3 years ago

8 0

True bc it is becoming energy

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If pressurized air pressure is 350 kPa, atmospheric pressure is 100 kPa, initial atmospheric pressure is 100 kPa, initial accele

Travka [436]

Answer:

$d=8.657mm$

Explanation:

From the question we are told that

Pressurized air pressure is $P_{air}=350 kPa,$

Atmospheric pressure is $P_a=100 kPa$

Initial acceleration of the water rocket is $a_i=0.5g.$

Acceleration of the water rocket is $a_r=0.5g$

Mass of water is $M_w=0.5 kg$

Generally total mass is given mathematically given as

$T_M=0.5+0.5=>1kg$

Generally the tension on the rocket is given mathematically given as

$T=(P_{air}-P_a)A$

$T=(350-100) \frac{\pi d^2}{4}$

T is also

$T=\frac{3Mg}{2}$

Therefore

$T=>(350-100) \frac{\pi d^2}{4}= \frac{3Mg}{2}$

$T=>(350-100) \frac{\pi d^2}{4}= \frac{3*1*9.81}{2}$

$d^2= \frac{3*1*9.81*4}{2(350-100) \pi}$

$d=\sqrt{\frac{3*1*9.81*4}{2(350-100) \pi}}$

$d=8.657mm$

therefore diameter of nozzle is mathematically given as

$d=8.657mm$

8 0

3 years ago

No wait... That's still not right... The cart was at the point x = 2.8 when t = 0.0 s, but it already had an initial velocity of

polet [3.4K]

Solution :

Velocity of cart at t = 0 s is, u = 1.8 m/s .

Distance covered in 3 seconds is :

d = 1.8 m/s × 3 s

d = 5.4 m.

So, position of cart after t = 3 seconds is x = 2.8 + 5.4 m = 8.2 m .

Hence, this is the required solution.

8 0

3 years ago

1. How does RNA differ from DNA?

9966 [12]

The answer is c) RNA contains uracil and ribose.

7 0

3 years ago

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What are 3d glasses made of?

masha68 [24]

<span>a) two filters with vertical polarization
</span>

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4 years ago

Read 2 more answers

A wire carries 3.7 A of current. A second wire is placed parallel to the first 8.0 cm away. What is the current flowing through

IgorC [24]

Answer:

The current in second wire is 5.0 A.

(B) is correct option.

Explanation:

Given that,

Current in first wire = 3.7 A

Distance = 8.0 cm

We need to calculate the magnetic field due to the current carrying wire

Using formula of magnetic field

$B=\dfrac{\mu_{0}I}{2\pi r}$

Where, I = current

r = distance

Put the value into the formula

For first wire

$B = \dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}$ ...(I)

For second wire,

The distance is 8-3.7 = 4.3 cm

$B' = \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}$ ...(II)

The magnetic field in both the wires,

From equation (I) and (II)

$\dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}= \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}$

$I'=\dfrac{3.7\times4.3\times10^{-2}}{3.4\times10^{-2}}$

$I'=4.68\ A\ approx = 5.0\ A$

Hence, The current in second wire is 5.0 A.

8 0

4 years ago

An electric motor transforms potential energy into mechanical energy.True or false ​

An electric motor transforms potential energy into mechanical energy.True or false