Answer:
a) P=0.25x10^-7
b) R=B*N2*E
c) N=1.33x10^9 photons
Explanation:
a) the spontaneous emission rate is equal to:
1/tsp=1/3 ms
the stimulated emission rate is equal to:
pst=(N*C*o(v))/V
where
o(v)=((λ^2*A)/(8*π*u^2))g(v)
g(v)=2/(π*deltav)
o(v)=(λ^2)/(4*π*tp*deltav)
Replacing values:
o(v)=0.7^2/(4*π*3*50)=8.3x10^-19 cm^2
the probability is equal to:
P=(1000*3x10^10*8.3x10^-19)/(100)=0.25x10^-7
b) the rate of decay is equal to:
R=B*N2*E, where B is the Einstein´s coefficient and E is the energy system
c) the number of photons is equal to:
N=(1/tsp)*(V/C*o)
Replacing:
N=100/(3*3x10^10*8.3x10^-19)
N=1.33x10^9 photons
Answer:
Thread.
Explanation:
The most common form consists of a cylindrical shaft with helical grooves or ridges called threads around the outside.
Answer:
Yes, the velocity of the object can reverse direction when its acceleration is constant. For example consider that the velocity of any object at any time t is given as: ... At At t = 0 sec, the magnitude of velocity is 2m/s and is moving in the forward direction i.e.v (t) = -2.
Explanation:
1. The kinetic energy of any object is calculated as :
...........(1)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of velocity, ![[v]=[LT^{-1}]](https://tex.z-dn.net/?f=%5Bv%5D%3D%5BLT%5E%7B-1%7D%5D)
![[ML^2T^{-2}]=\dfrac{1}{2}[M]([LT^{-1}])^2](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5Cdfrac%7B1%7D%7B2%7D%5BM%5D%28%5BLT%5E%7B-1%7D%5D%29%5E2)
So, ![[ML^2T^{-2}]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BML%5E2T%5E%7B-2%7D%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
LHS = RHS
2. The potential energy is given by :

Dimensional formula of mass is ![[M]](https://tex.z-dn.net/?f=%5BM%5D)
Dimensional formula of g is ![[LT^{-2}]](https://tex.z-dn.net/?f=%5BLT%5E%7B-2%7D%5D)
Dimensional formula of height is ![[L]](https://tex.z-dn.net/?f=%5BL%5D)
Dimensional formula of energy, ![[E]=[ML^2T^{-2}]](https://tex.z-dn.net/?f=%5BE%5D%3D%5BML%5E2T%5E%7B-2%7D%5D)
So, ![E=[M][LT^{-2}][L]](https://tex.z-dn.net/?f=E%3D%5BM%5D%5BLT%5E%7B-2%7D%5D%5BL%5D)
So, LHS = RHS
Hence, this is the required solution.
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