The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.
- The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.
Reasons:
The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;
Where;
a₀ = The current size of the Universe
a = The size of the early Universe = 5% of a
Therefore;
0.05 + 0.05·z = 1
- The redshift is of the observed light is, z = <u>19</u>
Learn more here:
brainly.com/question/14459434
brainly.com/question/3654558
The gravitational potential energy of the object is 100 J.
Gravitational potential energy stored in an object is the work done in raising the object to a height <em>h</em> against the gravitational force acting on it.
The gravitational force acting on a body is its weight mg, where m is its mass and g, the acceleration due to gravity.
Work done by a force is equal to the product of the force and the displacement made by the point of application of the force.
The weight of the object is given as 20 J and it is raised to a height of 5 m.
The gravitational potential energy of the object is 100 J.
Part A:
For this part we’re assuming all the kinetic energy of the moving bumper car is converted into elastic potential energy in the spring since the car is brought to rest. Therefore you can find the total kinetic energy to get your answer:
KE = ½ mv^2
KE = ½ (200)(8)^2
KE = 6400 J
Part B:
Now you can use Hooke’s law to find the force:
F = kx
F = (5000)(0.2)
F = 1000 N
Answer:
<u> </u><u>»</u><u> </u><u>Image</u><u> </u><u>distance</u><u> </u><u>:</u>
- v is image distance
- u is object distance, u is 10 cm
- f is focal length, f is 5 cm
<u> </u><u>»</u><u> </u><u>Magnification</u><u> </u><u>:</u>
• Let's derive this formula from the lens formula:
» Multiply throughout by fv
• But we know that, v/u is M
- v is image distance, v is 10 cm
- f is focal length, f is 5 cm
- M is magnification.
<u> </u><u>»</u><u> </u><u>Nature</u><u> </u><u>of</u><u> </u><u>Image</u><u> </u><u>:</u>
- Image is magnified
- Image is erect or upright
- Image is inverted
- Image distance is identical to object distance.
The amount of gravitational potential energy acquired by the rock is equal to:
where
m is the mass of the rock
g is the gravitational acceleration
is the increase in height of the rock
Substituting the data of the problem, we find
So, Natalie gave 220.7 J of energy to the rock.
