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pav-90 [236]
3 years ago
9

If a circular loop of wire of radius 19.7 cm is located in a region where the spatially uniform magnetic field perpendicular to

the plane of the loop is changing at a rate of +2.0 ✕ 10−3 T/s, find the value of the induced EMF in this loop due to this changing magnetic field.
Physics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

Magnitude of induced emf will be 2.437\times 10^{-3}volt

Explanation:

We have given radius of the circular loop r = 19.7 cm = 0.197 m

So area of the circular loop A=\pi r^2=3.14\times 0.197^2=0.1218m^2

It is given that magnetic field is changing as 2\times 10^{-3}T/sec

Emf induced in the circular loop is equal to e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}

So emf induced will be equal to e=\frac{-d\Phi }{dt}=-0.1218\times2\times 10^{-3}=2.437\times 10^{-3}volt

So magnitude of induced emf will be 2.437\times 10^{-3}volt

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A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.6 m/s . Two seconds later t
dybincka [34]

Answer:

A) t = 7.0 s    

B) x = 25 m  

C) v = 10 m/s

Explanation:

The equations for the position and velocity of an object traveling in a straight line is given by the following expressions:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

A)When both friends meet, their position is the same:

x bicyclist = x friend

x0 + v0 · t + 1/2 · a · t² = x0 + v · t

If we place the center of the frame of reference at the point when the bicyclist starts following his friend, the initial position of the bicyclist will be 0, and the initial position of the friend will be his position after 2 s:

Position of the friend after 2 s:

x = v · t

x = 3.6 m/s · 2 s = 7.2 m

Then:

1/2 · a · t² = x0 + v · t       v0 of the bicyclist is 0 because he starts from rest.

1/2 · 2.0 m/s² · t² = 7.2 m + 3.6 m/s · t

1  m/s² · t² - 3.6 m/s · t - 7.2 m = 0

Solving the quadratic equation:

t = 5.0 s

It takes the bicyclist (5.0 s + 2.0 s) 7.0 s to catch his friend after he passes him.

B) Using the equation for the position, we can calculate the traveled distance. We can use the equation for the position of the friend, who traveled over 7.0 s.

x = v · t

x = 3.6 m/s · 7.0 s = 25 m

(we would have obtained the same result if we would have used the equation for the position of the bicyclist)

C) Using the equation of velocity:

v = a · t

v = 2.0 m/s² · 5.0 s = 10 m/s

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Structures on a bird feather act like a diffraction grating having 8000 8000 lines per centimeter. What is the angle of the firs
sammy [17]

Answer:

Angle of first order maximum, \theta=21.19^{\circ}

Explanation:

Given that,

Wavelength of the light, \lambda=452\ nm=452\times 10^{-9}\ m

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d=\dfrac{1}{N}

d=\dfrac{1}{8000/cm}  

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The equation of grating is given by :

d\ sin\theta=n\lambda

n = 1

sin\theta=\dfrac{\lambda}{d}

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Dvinal [7]

Answer:

Amoebas have projections called pseudopods

Explanation:

Pseudopodia is the locomatary organ of amoeba. It helps them in movement and transportation.

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