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pav-90 [236]
3 years ago
9

If a circular loop of wire of radius 19.7 cm is located in a region where the spatially uniform magnetic field perpendicular to

the plane of the loop is changing at a rate of +2.0 ✕ 10−3 T/s, find the value of the induced EMF in this loop due to this changing magnetic field.
Physics
1 answer:
Alisiya [41]3 years ago
6 0

Answer:

Magnitude of induced emf will be 2.437\times 10^{-3}volt

Explanation:

We have given radius of the circular loop r = 19.7 cm = 0.197 m

So area of the circular loop A=\pi r^2=3.14\times 0.197^2=0.1218m^2

It is given that magnetic field is changing as 2\times 10^{-3}T/sec

Emf induced in the circular loop is equal to e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}

So emf induced will be equal to e=\frac{-d\Phi }{dt}=-0.1218\times2\times 10^{-3}=2.437\times 10^{-3}volt

So magnitude of induced emf will be 2.437\times 10^{-3}volt

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Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

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Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

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Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

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Have a nice day!

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