Since the coefficient of NH3 is 2, 100.4 kJ of heat is released when 2 moles of NH3 are formed. So, when one mole of NH3 is formed, half of the heat would be produced or 50.2 kJ.
Your answer, IMHO, is correct.
The detailed work is below:
1) to calculate the mass of one mole of nitrogen dioxide (NO₂): 14+2*16=46 (gr/mole);
it means, the mass of 1 mole of NO₂ is 46 gramms. Then
2) to calculate the space in milliliteres: V=mass/density=46/1.5=30.(6) (millilitres)≈31 ml.
439.3 g CO2
Explanation:
First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:
3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)
= 9.981 mol CO2
Use the molar mass of CO2 to determine the # of grams of CO2:
9.981 mol CO2 x (44.01 g CO2/1 mol CO2)
= 439.3 g CO2
Number of atoms : 1.26 x 10²³
<h3>Further explanation </h3>
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
0.21 moles of Al, so n = 0.21
Number of atoms :
