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antoniya [11.8K]

3 years ago

14

A mass oscillating up and down while attached to the bottom of a spring can be modeled using simple harmonic motion. If the weig

ht is displaced from its equilibrium position a maximum of 7 centimeters and it takes 3 seconds to complete one cycle, answer the following questions:
Amplitude: Period: Frequency:

2 answers:

sp2606 [1]3 years ago

4 0

MARK THE OTHER DUDE BRAINLIEST

Amplitude = 7 cm

Period = 3 seconds

Frequency = 0.33 Hz

Ne4ueva [31]3 years ago

3 0

Amplitude is the maximum displacement so 7 cm
Period is the time taken to complete one cycle so 3 seconds
Frequency is the inverse of time period, or the number of cycles per second so 1/3 = 0.33 Hz

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What is perfect machine?Why is this machine not possible in the real life?

andrezito [222]

Explanation:

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5 0

2 years ago

Guys please help me

Likurg_2 [28]

Answer:

1) $t=2.26\: s$

2) $S=33.9\: m$

3) $v=26.77\: m/s$

4) $\alpha=55.92$

Explanation:

1)

We can use the following equation:

$y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}$

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

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2)

The equation of the motion in the x-direction is:

$v_{ix}=\frac{S}{t}$

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$S=33.9\: m$

3)

The velocity in the y-direction of the stone will be:

$v_{fy}=v_{iy}-gt$

$v_{fy}=0-(9.81*2.26)$

$v_{fy}=-22.17\: m/s$

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

$v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}$

$v=26.77\: m/s$

4)

The angle of this velocity is:

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I hope it helps you!

6 0

3 years ago

A train starts from rest and travels for 5.0 s with a uniform acceleration of 1.5 m/s2. What is the final velocity of the train?

alexandr1967 [171]

Answer:

Final speed of the train is 7.5 m/s

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7 0

3 years ago

Read 2 more answers

base your answer to this question on the information below and on your knowledge of physics. A toy launcher that is used to laun

Nadya [2.5K]

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3 0

3 years ago