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Tju [1.3M]
3 years ago
8

Does gender affect your aerobic capacity?

Physics
1 answer:
alekssr [168]3 years ago
8 0
To a degree yes, the mass and volume of a male is far greater than that of the opposite gender. As well as the type of aerobics , but with practice and daily aerobics activities one can become very flexible
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Before designing the filter, one must understand the relationship between the output voltage of the circuit and the frequency. F
Kamila [148]

Answer:

Option b. is correct

Explanation:

An RLC electrical circuit consists of constituent components: a resistor (R), an inductor (L), and a capacitor (C). A resistor, an inductor, and a capacitor are connected in series or parallel.

The impedances of the circuit elements depend on the frequency.

Both impedance magnitudes decrease when the frequency increases

5 0
2 years ago
If the mass of a person is 600kg on Earth what is the persons mass on the moon
nika2105 [10]

Answer:

The mass of the person would remain 600kg.

Explanation:

mass refers to the amount of matter in a particular object. therefore even though the moon has less gravitational force than the Earths, it still would have the same mass since the person is made up of the same amount of matter on Earth and in the moon.

when asked about weight, it would be 1000N. but in mass , same 600kg.

3 0
3 years ago
Pleaseee someone help me TEST TOMORROW
Liono4ka [1.6K]
3.A

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5.A
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4 0
3 years ago
Read 2 more answers
Rotational dynamics about a fixed axis: A person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface
FrozenT [24]

Answer:

I = 2 kgm^2

Explanation:

In order to calculate the moment of inertia of the door, about the hinges, you use the following formula:

\tau=I\alpha     (1)

I: moment of inertia of the door

α: angular acceleration of the door = 2.00 rad/s^2

τ: torque exerted on the door

You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:

\tau=Fd        (2)

F: force = 5.00 N

d: distance to the hinges = 0.800 m

You replace the equation (2) into the equation (1), and you solve for α:

Fd=I\alpha\\\\I=\frac{Fd}{\alpha}

Finally, you replace the values of all parameters in the previous equation for I:

I=\frac{(5.00N)(0.800m)}{2.00rad/s^2}=2kgm^2

The moment of inertia of the door around the hinges is 2 kgm^2

3 0
3 years ago
Which of these factors determines soil texture?
STatiana [176]
It is B particle sizes
8 0
3 years ago
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