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ohaa [14]
3 years ago
12

An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion

can you draw about the initial kinetic energy of the electron

Physics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

attached below is the free body diagram of the missing  illustration

Initial kinetic energy of the electron = 3 eV

Explanation:

The conclusion that can be drawn about the kinetic energy of the electron is

E_{e} = E_{3}  - E_{1}

E_{e} = initial kinetic energy of the electron

E_{1} = -4 eV

E_{3} = -1 eV

insert the values into the equation above

E_{e} = -1 -(-4)  eV

   = -1 + 4 = 3 eV

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Math the following to definitions
Leona [35]
Hi,
The answer should be:
Vector 5
Magnatude 4
Weight 1
Mass 2
Net force 6
Force 3

Hope this helps!
6 0
3 years ago
What does it mean for their to be a net force on an object vs no net force? Which one is described as balanced forces and which
STatiana [176]
It’s like the force put against something or someone✨
3 0
3 years ago
A seashell is suspended in the air at rest by two strands of spider silk. Each strand of silk makes an angle of 75 degrees above
Ksenya-84 [330]

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

  • <em>Tension on each strand of silk, T = 1.42 N</em>
  • <em>Angle of inclination of each strand, θ = 75⁰</em>

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0

where;

  • W is the weight of the seashell

The weight of the seashell is calculated as;

1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N

The mass of the seashell is calculated as follows;

W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

Learn more about equilibrium forces here: brainly.com/question/8045102

5 0
3 years ago
An ideal parallel-plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is connect
Elina [12.6K]

Answer:

e) half

Explanation:

as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is

Q = CV ...........(i)

we also know capacitance of a capacitor for separation d and area A is

C = ∈₀A/d ...........(ii)

from  the above equation it is clear that C is inversely proportional to separation  if separation doubled  capacitance will reduced to half   and from equation first charge is directly proportional to capacitance.

that s why magnitude of charge will reduced to half  

so option (e) is right answer

3 0
3 years ago
To make a pendulum, a 210 g ball is attached to one end of a string that has a length of 1.2 m and negligible mass. (The other e
lakkis [162]

Answer:

a) v \approx 1.233\,\frac{m}{s}, b) v \approx 1.426\,\frac{m}{s}, c) \theta_{2} \approx 22.61^{\textdegree}

Explanation:

a) The speed of the ball is determined by applying the Principle of Energy Conservation:

U_{g,1} + K_{1} = U_{g,2} + K_{2}

The speed of the ball when the string makes an angle of 12° with the vertical is:

K_{2} = U_{g,1} - U_{g,2} + K_{1}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot L \cdot [(1-\cos \theta_{1})-(1 -\cos \theta_{2})]

v = \sqrt{2\cdot g \cdot L \cdot (\cos \theta_{2} - \cos \theta_{1})}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (1.2\,m)\cdot (\cos 12^{\textdegree}-\cos 24^{\textdegree})}

v \approx 1.233\,\frac{m}{s}

b) The maximum speed of the ball is:

v = \sqrt{2\cdot g \cdot L \cdot (\cos \theta_{2} - \cos \theta_{1})}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (1.2\,m)\cdot (\cos 0^{\textdegree}-\cos 24^{\textdegree})}

v \approx 1.426\,\frac{m}{s}

c) The angle between the string and the vertical when the speed of the ball is one-third its maximum value is obtained by proving different values of \theta_{2}. The solution is approximately:

\theta_{2} \approx 22.61^{\textdegree}

5 0
3 years ago
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