Hi,
The answer should be:
Vector 5
Magnatude 4
Weight 1
Mass 2
Net force 6
Force 3
Hope this helps!
It’s like the force put against something or someone✨
The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
- <em>Tension on each strand of silk, T = 1.42 N</em>
- <em>Angle of inclination of each strand, θ = 75⁰</em>
The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

where;
- W is the weight of the seashell
The weight of the seashell is calculated as;

The mass of the seashell is calculated as follows;

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
Learn more about equilibrium forces here: brainly.com/question/8045102
Answer:
e) half
Explanation:
as we know relation b/w charge(Q) , capacitance (C) and voltage (V) is
Q = CV ...........(i)
we also know capacitance of a capacitor for separation d and area A is
C = ∈₀A/d ...........(ii)
from the above equation it is clear that C is inversely proportional to separation if separation doubled capacitance will reduced to half and from equation first charge is directly proportional to capacitance.
that s why magnitude of charge will reduced to half
so option (e) is right answer
Answer:
a)
, b)
, c) 
Explanation:
a) The speed of the ball is determined by applying the Principle of Energy Conservation:

The speed of the ball when the string makes an angle of 12° with the vertical is:

![\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot L \cdot [(1-\cos \theta_{1})-(1 -\cos \theta_{2})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%20%5Ccdot%20v%5E%7B2%7D%20%3D%20m%5Ccdot%20g%20%5Ccdot%20L%20%5Ccdot%20%5B%281-%5Ccos%20%5Ctheta_%7B1%7D%29-%281%20-%5Ccos%20%5Ctheta_%7B2%7D%29%5D)



b) The maximum speed of the ball is:



c) The angle between the string and the vertical when the speed of the ball is one-third its maximum value is obtained by proving different values of
. The solution is approximately:
