answer:
- <em>Xi</em><em> </em>+ Xf =10km+30km=60km
An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion
can you draw about the initial kinetic energy of the electron
1 answer:
Answer:
attached below is the free body diagram of the missing illustration
Initial kinetic energy of the electron = 3 eV
Explanation:
The conclusion that can be drawn about the kinetic energy of the electron is
E = initial kinetic energy of the electron
E = -4 eV
E = -1 eV
insert the values into the equation above
= -1 -(-4) eV
= -1 + 4 = 3 eV
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Answer:
8.91 J
Explanation:
mass, m = 8.20 kg
radius, r = 0.22 m
Moment of inertia of the shell, I = 2/3 mr^2
= 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2
n = 6 revolutions
Angular displacement, θ = 6 x 2 x π = 37.68 rad
angular acceleration, α = 0.890 rad/s^2
initial angular velocity, ωo = 0 rad/s
Let the final angular velocity is ω.
Use third equation of motion
ω² = ωo² + 2αθ
ω² = 0 + 2 x 0.890 x 37.68
ω = 8.2 rad/s
Kinetic energy,
K = 0.5 x 0.265 x 8.2 x 8.2
K = 8.91 J