Making a list helps organize the information in a word problem that can otherwise be overwhelming and confusing. Making lists put out a straightforward guide and help you break down the problem so you really understand what you need to do.
Word problem:
Maya has $55 and she gives her brother $10. She also gives her friend $15 and her sister $5. Her sister pays her back fully but her brother only pays back half of what he owed, promising to pay her back later. Her friend gives back 1/3 of what she owed, also promising to pay her back as soon as she can. How much money does Maya currently have?
In this problem, you have to process the money transactions and making a list will help you go step by step.
Answer:
Statements 3, 4 and 5 are true.
Step-by-step explanation:
x^2 - 8x + 4
Using the quadratic formula:
x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2
= (8 +/- √(64 - 16)) / 2
= 4 +/- √48 / 2
= 4 +/- 4√3/2
= 4 +/- 2√3.
So the third statement is true.
Converting to vertex form:
x^2 - 8x + 4
= (x - 4)^2 - 16 + 4
= (x - 4)^2 -12
So the extreme value is at (4, -12)
So the fourth statement is true.
The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.
Ralph is 3 years old
Casey is 18 years old
Step-by-step explanation:
Let the age of Ralph be x
Then Casey is 6 times as old as Ralph will be 6x
In two years
Ralph =x+2
Casey=6x+2 ⇒ 4(x+2)
Equate the two equations for Casey as
6x+2 = 4x+8
6x-4x=8-2
2x=6
x=6/2= 3
Current age;
Ralph= x= 3 years old
Casey=6x = 6*3= 18 years
Learn More
Forming expressions and solving equations;brainly.com/question/1280754
Keywords :six, times, years
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Where is the table? You could potentiallysolve this by deconstructing the function.
<u>Answer:</u>
<em>Number of calories in one slice of a 14 inch pizza is 189.825.
</em>
<u>Step-by-step explanation:</u>
Given that 6 inch pizza has <em>650 calories.
</em>
Therefore 1 inch pizza has 
<em>calories.
</em>
14 inch pizza will have
Given that the 14 inch pizza is divided into 8 slices.
Therefore each slice of the 14 inch pizza will have
<em>
</em>
