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xz_007 [3.2K]
3 years ago
10

P

Chemistry
1 answer:
BARSIC [14]3 years ago
6 0

5.426 x 10^{22} molecules are there in a deep breath of air whose volume is 2. 35 L at body temperature 36 C and a pressure of 740 torr.

Explanation:

Data given:

volume V = 2.35 L

Temperature T = 36 Degrees or 273.15 + 36 = 309.15 K

pressure P = 740 torr OR 0.973 Atm

R = 0.08205 L atm / mole K

n (number of molecules of gas)= ?

The formula used will be

PV = nRT

Putting the value of given variables in above equation:

n = \frac{PV}{RT}

 = \frac{0.973 x 2.35}{0.08205 x 309.15}

 = 0.0901 moles

According to Avagadro' s law that gases at equal volume, temperature and pressure contains same molecules.

number of molecules:

number of moles x avagadro number

0.0901 x 6.02 x 10^{23}

= 0.54 x 10^{23}

= 5.426 x 10^{22} molecules.

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The two general types of air pollution are _____ and _____.
Verizon [17]
Liquid and gases is the two general types of air pollution
5 0
3 years ago
Give the Unabbreviated electron configuration for barium
Shalnov [3]

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n =  2 +     8    +    8     +       18       +       18       +  2 = 56

8 0
4 years ago
An enclosed vessel contains 2.5g of 9b nitrogen and 13.3g of chlorine at s.T.P. Of What will be the partial pressure of the Il n
kow [346]

Answer:

0.535 atm

Explanation:

Since the volume of the tank is constant, we use Gay- Lussac's law to find the pressure at 180°C.

So, P₁/T₁ = P₂/T₂ where P₁ = pressure at S.T.P = 1 atm, T₁ = temperature at S.T.P = 273.15 K, P₂ = pressure of gas at 180 °C and T₂ = 180 °C = 273.15 + 180 K = 453.15 K

So, P₁/T₁ = P₂/T₂

P₂ = P₁T₂/T₁

Substituting the values of the variables into the equation, we have

P₂ = P₁T₂/T₁

P₂ = 1 atm × 453.15 K/273.15 K

P₂ = 1 atm × 1.66

P₂ = 1.66 atm

We now need to find the total number of moles of each gas present

number of moles of nitrogen = mass of nitrogen, m/molar mass of nitrogen molecule M

n = m/M

m = 2.5 g and M = 2 × atomic mass of nitrogen (since it is diatomic) = 2 × 14 g/mol = 28 g/mol

So, n = 2.5 g/28 g/mol

n = 0.089 mol

number of moles of chlorine, n' = mass of chlorine, m'/molar mass of chlorine molecule M'

n' = m'/M'

m' = 13.3 g and M = 2 × atomic mass of chlorine (since it is diatomic) = 2 × 35.5 g/mol = 71 g/mol

So, n' = 13.3 g/71 g/mol

n' = 0.187 mol

So, the total number of moles of gas present is n" = n + n' = 0.089 mol + 0.187 mol = 0.276 mol

So, the partial pressure due to nitrogen gas, P = mole fraction of nitrogen × pressure of gas at 180 °C

P = n/n" × P₂

P = 0.089 mol/0.276 mol × 1.66 atm

P = 0.322 × 1.66 atm

P = 0.535 atm

8 0
3 years ago
How many molecules are in the substance formula of 2C6H1206 (use coefficients)
FrozenT [24]

<u>Answer:</u> The number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

<u>Explanation:</u>

Formula units are defined as the number of molecules or atoms present in 1 mole of a compound or element respectively.

According to mole concept:

1 mole of a compound contains 6.022\times 10^{23} number of formula units

Here, 2 represents the number of moles of C_6H_{12}O_6

We are given:

Moles of C_6H_{12}O_6 (glucose) = 2 moles

Number of formula units of C_6H_{12}O_6=(2\times 6.022\times 10^{23})=1.2044\times 10^{24}

Hence, the number of formula units present in 2 moles of C_6H_{12}O_6 are 1.2044\times 10^{24}

6 0
3 years ago
How many moles are in 156 grams of potassium???<br><br><br> I already tried to ask google : (
Y_Kistochka [10]

Answer:

1 mole is equal to 1 moles Potassium, or 39.0983 grams.

39.0983g X 4 = 156.3932

so 4 moles are in 156 grams of Potassium

Explanation:

Hope this helps

-A Helping Friend (mark brainliest pls)

5 0
4 years ago
Read 2 more answers
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