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xz_007 [3.2K]
2 years ago
10

P

Chemistry
1 answer:
BARSIC [14]2 years ago
6 0

5.426 x 10^{22} molecules are there in a deep breath of air whose volume is 2. 35 L at body temperature 36 C and a pressure of 740 torr.

Explanation:

Data given:

volume V = 2.35 L

Temperature T = 36 Degrees or 273.15 + 36 = 309.15 K

pressure P = 740 torr OR 0.973 Atm

R = 0.08205 L atm / mole K

n (number of molecules of gas)= ?

The formula used will be

PV = nRT

Putting the value of given variables in above equation:

n = \frac{PV}{RT}

 = \frac{0.973 x 2.35}{0.08205 x 309.15}

 = 0.0901 moles

According to Avagadro' s law that gases at equal volume, temperature and pressure contains same molecules.

number of molecules:

number of moles x avagadro number

0.0901 x 6.02 x 10^{23}

= 0.54 x 10^{23}

= 5.426 x 10^{22} molecules.

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Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .
gavmur [86]
The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:

264 × 2.70 = (m÷264) × 264

264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.
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3 years ago
Consider a neutrally charged atom that has an atomic mass number of 80, which includes 35 neutrons. how many electrons does this
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olga2289 [7]
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CO2 is an element. True False
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Answer:False

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What is the molarity of a NaCl stock used to make 750 ml of a dilute 10 mM solution if 5 ml of the concentrated solution was use
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Explanation:

The given data is as follows.

          M_{1} = 10 mM = 10 \times 10^{-3} M

          V_{1} = 750 ml,           V_{2} = 5 ml

          M_{2} = ?

Therefore, calculate the molarity of given NaCl stock as follows.

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