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kow [346]
3 years ago
13

If you add salt continuously to a glass of water, eventually some salt will remain at the bottom. why?

Chemistry
2 answers:
nadya68 [22]3 years ago
5 0
If you keep adding salt, the amount of salt and water will eventually pass equilibrium (for which every water molecule has a salt). This results in the remaining salt not being able to dissociate. 
GREYUIT [131]3 years ago
3 0
Http://www.lcmrschooldistrict.com/demers/cbphysicalscience/Chp%208-3%20Solubility%20and%20Concentrat...

This website helped me understand the concept.
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33.23 grams of a thin sheet of iron is completely oxidized in 7 days. How would you express the rate of conversion of the silver
tresset_1 [31]

Answer:

A. 0.0440 moles/day

Explanation:

First, let's figure out how many moles 33.23 grams of silver is. We do this by dividing the number of grams by the molar mass of silver, which is 107.87 g/mol:

33.23 g Ag ÷ 107.87 g/mol = 0.3081 mol Ag

Now, let's divide this by 7 to get the rate per day:

0.3081 mol Ag ÷ 7 days = 0.0440 mol/day

Thus, the answer is A.

7 0
4 years ago
Balance the following equation. __AI+ __CuO __AI203+ _Cu
Nesterboy [21]
2 Al+ 3 CuO-> 1 Al2O3+ 3Cu
7 0
3 years ago
Alkanes are chains of carbon atoms surrounded by hydrogen atoms. <br><br> a. True<br> b. False
Ne4ueva [31]

Answer:

a. True

Explanation:

Alkanes are chains of carbon atoms surrounded by hydrogen atoms. TRUE.

Alkanes are hydrocarbons, that is, they are organic compounds formed only by carbon and hydrogen. In alkanes, carbon atoms are bonded to each other through single covalent bonds and they are also bonded to hydrogen atoms through the same type of bonds. Alkanes have the general formula CnH2n+2.

7 0
3 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
3 years ago
One scientific investigation may result in
Paladinen [302]

Answer:

a new discover a new theory

4 0
3 years ago
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